Use both!
You want to minimize <em>P</em>, so differentiate <em>P</em> with respect to <em>x</em> and set the derivative equal to 0 and solve for any critical points.
<em>P</em> = 8/<em>x</em> + 2<em>x</em>
d<em>P</em>/d<em>x</em> = -8/<em>x</em>² + 2 = 0
8/<em>x</em>² = 2
<em>x</em>² = 8/2 = 4
<em>x</em> = ± √4 = ± 2
You can then use the second derivative to determine the concavity of <em>P</em>, and its sign at a given critical point decides whether it is a minimum or a maximum.
We have
d²<em>P</em>/d<em>x</em>² = 16/<em>x</em>³
When <em>x</em> = -2, the second derivative is negative, which means there's a relative maximum here.
When <em>x</em> = 2, the second derivative is positive, which means there's a relative minimum here.
So, <em>P</em> has a relative maximum value of 8/(-2) + 2(-2) = -8 when <em>x</em> = -2.
Answer:
There is not enough info to complete this question. A function is needed so you can plug in -3 and 5
Step-by-step explanation:
Hello!
Find the inverse by swapping the x and y variables:
Begin simplifying. Multiply both sides by 4y - 5:
Start isolating for y by subtracting 2 from both sides:
Distribute x:
Move the term involving y (4yx) over to the other side:
Factor out y and divide:
Use this equation to evaluate 
Answer:
<h2><u>
4 quarters, 10 dimes</u></h2>
Step-by-step explanation:
x + y = 14 --> x = 14 - y
$0.10x + $0.25y = $2.00, or 10x + 25y = 200
- we can plug this value for x from the first equation into the second:
10(14 - y) + 25y = 200
140 - 10y + 25y = 200
140 + 15y = 200
15y = 60
y = 4 --> 4 quarters ($0.25 x 4 = $1.00)
if y = 4, then x = 14 - y --> x = 10 --> 10 dimes (0.10 x 10 = $1.00)
matches the second equation where these add up to $2.00
