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Mila [183]
4 years ago
11

Write the slope intercept form of an equation that passes through the point and is perpendicular to the graph of the equation (2

,-4), 2x-3 y=9
Mathematics
1 answer:
Alex_Xolod [135]4 years ago
3 0

Answer:

The perpendicular line would be y = -3/2x - 1

Step-by-step explanation:

First we have to solve the first equation for y.

2x - 3y = 9

-3y = -2x + 9

y = 2/3x - 3

In order to find the equation of this line, we first have to note that perpendicular lines have opposite and reciprocal slopes. Therefore, since the original line has a slope of 2/3, we know the new line will have a slope of -3/2. Now we can use that information along with the given point in point-slope form to find the equation.

y - y1 = m(x - x1)

y + 4 = -3/2(x - 2)

y + 4 = -3/2x + 3

y = -3/2x - 1

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