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den301095 [7]
3 years ago
13

The sum of the measures of the angles of a triangle is 180 degrees°. The smallest angle of the triangle has a measure one fourth

1 4 the measure of the second smallest angle. The largest angle has a measure that is 2020 degrees° less than 55 times the measure of the second smallest angle. Determine the measure of each angle.
Mathematics
1 answer:
vivado [14]3 years ago
6 0

Answer:

8°,32°,140°.

Step-by-step explanation:

Sum of measure of angles of a triangle is 180°

Let the second smallest angle be x°

Smallest angle=\frac{1}{4} x

Largest angle= 5 x- 20°

A T Q

x+ \frac{1}{4} x + 5x-20= 180°

\frac{4x+x+20x}{4} = 180+ 20

\frac{25x}{4} = 200

x= \frac{200}{25} × 4

x= 32°'

Smallest angle is 32°

Hence, the smallest angle is \frac{1}{4} x= \frac{1}{4}×32°= 8°

Largest angle is 5x- 20= 5×32- 20= 140°

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Step-by-step explanation:

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3^4+4.5= Input whole number
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Step-by-step explanation:

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Travis travel 248 miles in 4 hours what is his unit rate of speed in miles per hour
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USPshnik [31]

Answer:

47.62 cm

Step-by-step explanation:

ABCD is a rhombus. Each side measures 15 cm.

m<A = 60°.

Here are some properties of a rhombus:

Opposite angles of a rhombus are congruent.

m<C = m<A = 60°

m<ADC = m<ABC

The sum of the measures of the interior angles of a quadrilateral is 360°.

The diagonals are perpendicular bisectors of each other.

m<A + m<C + m<ADC + m<ABC = 360°

60° + 60° + 2m<ADC = 360°

2m<ADC = 240°

m<ADC = 120°

Each diagonal of a rhombus bisects a pair of congruent, opposite angles.

m<ADB + m<CDB = m<ADC

m<ADB = m<CDB

m<ADB + m<ADB = 120°

m<ADB = 60°

Triangle ABD had two angles, <A and <ADB, that measure 60°. Therefore, the third angle, <ABD also measures 60°. That makes triangle ABD an equilateral triangle.

Draw segment AT.

T is the midpoint of BD. The segment AT is the perpendicular bisector of segment BD. Triangle ATD is a 30-60-90 triangle.

Using the ratio of the lengths of the sides of a 30-60-90 triangle, we can calculate the length of AT which is the radius of circle A.

TD : AT : AD

1    : √3 :   2

AD = 15 cm

TD = AD/2

AT = √3 × TD

AT = (AD√3)/2

AT = 7.5√3 = 12.99

AQ = 12.99

perimeter = QD + PB + m(arc)PTQ + BC + CD

perimeter = (15 - 12.99) + (15 - 12.99) + 60°/360° × 2π(12.99) + 15 + 15

perimeter = 47.62

Answer: perimeter = 47.62 cm

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3 years ago
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