Answer:
So, y = 2x + 7;
Then, 2x = 4( 2x + 7 ) - 16;
2x = 8x + 28 - 16;
2x = 8x + 12;
- 6x = 12;
x = - 2;
Then, y = 2· (-2) + 7;
y = - 4 + 7;
y = 3.
Step-by-step explanation:
Answer:
1. A = 2x; P = 4x+2. A = 4; P = 10.
2. A = y² +2; P = 4y +2. A = 27; P = 22.
Step-by-step explanation:
1. The area is the sum of the marked areas of each of the tiles:
A = x + x
A = 2x
__
The perimeter is the sum of the outside edge dimensions of the tiles. Working clockwise from the upper left corner, the sum of exposed edge lengths is ...
P = 1 + (x-1) + x + 1 + (x+1) + x
P = 4x +2
__
When x=2, these values become ...
A = 2·2 = 4 . . . . square units
P = 4·2+2 = 10 . . . . units
_____
2. Again, the area is the sum of the marked areas:
A = y² + 1 + 1
A = y² +2
__
The edge dimension of the square y² tile is presumed to be y, so the perimeter (starting from upper left) is ...
P = y +(y-2) +1 +2 +(y+1) +y
P = 4y +2
__
When y=5, these values become ...
A = 5² +2 = 27 . . . . square units
P = 4·5 +2 = 22 . . . . units
The one in the middle you can tell because when x=0 that is the y intercept and the graph had a y intercept of 4 and the middle graph had 5
The correct match of each tile of the equation with its solution is:
- n - 13 = - 12 →→→ 1
- n/5 = -1/5 →→→ -1
- n + 15 = - 10 →→→ -25
<h3>How do we match each tile to the correct box?</h3>
To match each tile to the correct box, we have to solve the arithmetic operations in the box, then drag the correct tile that matches our answer into the box.
From the image attached below;
1.
n - 13 = - 12
Let us add (+13) to both sides to eliminate (-13), i.e.
n - 13 + 13 = - 12 + 13
n = 1
2.
n/5 = -1/5
multiply both side by 5
n/5 × (5) = -1/5 × (5)
n = -1
3.
n + 15 = - 10
n +15 - 15 = - 10 - 15
n = -25
Learn more about matching each tile to the correct box here:
brainly.com/question/17203448
#SPJ1
The expression represents a straight line equation of the form y=mx+c. where m is the slope and c is the y-intercept. From the given expression,
m=1.10 and c=0
therefore since a(w)=1.10w+0 is a straight line equation, the domain of the equation will be:
(-∞,∞)
and the range will be:
(-∞,∞)
This is because the domain and range of the straight line is always (-∞,∞).
