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My name is Ann [436]
3 years ago
9

Audrey had $20 and brought him for $1.10, a soda for $.99, and a bag of chips for $3.98. how much money does she have left

Mathematics
1 answer:
topjm [15]3 years ago
3 0
 The correct answwere is that he  has $14.13 left 
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Can someone help answer this?
katrin [286]

9√2 is squared first.

so its 162.

now according to Pythagoras theorem,

x2+x2=162

2x^2= 162

x^2= 162÷2

x^2= 81

x= √81

x=9

4 0
3 years ago
Read 2 more answers
Daisy, the african elephant weighs 10,250 pounds. The daily feed intake for an elephant is approximately 1.5% of the animals bod
AlexFokin [52]

Answer: a) 154 kilograms

Step-by-step explanation:

Given :  Daisy, the african elephant weighs 10,250 pounds.

The daily feed intake for an elephant is approximately 1.5% of the animals body weight.

1.5% can be written as 0.015.

Now, the amount of feed is to be feed to Daisy to meet her requirements will be :_

0.015\times10250=153.75\approx154

Hence, 154 kilograms of feed is to be feed to Daisy to meet her requirements.

4 0
3 years ago
Do supplementary angles form right angles? yes or no
Anuta_ua [19.1K]

Answer:

Yes i

Step-by-step explanation:

A supplementary angle can be two angles that sum up to 180 if you want you can have 2 angles that are 90 degrees that add up to 180 so therefore that would make a right angle.

6 0
3 years ago
I really need help with this question
Naily [24]

Answer:

7/12.

Step-by-step explanation:

Let's go over the details.

Box A contains 3, 5, and 6, and 9. Box B contains 1, 4, and 7.

Only 1 card is picked from each box.

For the sake of simplicity, let's take a step back. Let's assume that the actual values of the cards only indicate whether they are odd or even. So, we can replace the values with O for odd and E for even.

Box A now contains O(3), O(5), E(6), O(9), and Box B now contains O(1), E(4), O(7).

From logic, we can deduce that O + O = E, E + E = E, and E + O = O.

We're only looking at the combinations that result in an even sum. So we're specifically looking for OO and EE combinations.

Now that we know what we're looking for, we can go back to original problem.

There are a total of 12 possibilities if you use the values of the cards. Therefore, there is a \frac{1}{12} chance that you will get a specific combination.

To find the probability of getting a specific combination, you need to multiply the number of cards from Box A with the number of cards in Box B. So the possible combinations would be:

(3,1), (5,1), (6,1), (9,1), (3,4), (5,4), (6,4), (9,4), (3,7), (5,7), (6,7), (9,7)

But since we're looking only for (O,O) and (E,E) combinations, we can ignore all of the (O,E) and (E,O) combinations.

(3,1), (5,1), (9,1), (6,4), (3,7), (5,7), (9,7)

These account for 7 of the 12 possible combinations.

So the probability of getting two numbers whose sum is even, or (to put it in simpler terms) the probability of getting an OO or EE combination, is \frac{7}{12}.

4 0
3 years ago
4) After solving a rational equation you must check your solutions in the
Ludmilka [50]

Answer: D) To make sure the value does not make the denominator 0.​

We cannot divide by zero. Something like 1/0 is undefined. So it's important to check all potential solutions to make sure you don't get 0 in the denominator.

4 0
3 years ago
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