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REY [17]
3 years ago
9

Based on the picture below. find the angle measure for lmn.

Mathematics
1 answer:
trasher [3.6K]3 years ago
5 0

Answer:

Step-by-step explanation:

4x + 2x = 90

6x = 90

x = 15

4(15)= 60 for <LMN

2(15)= 30

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8i-(12-4i)+7√-9<br><br> show work please
Tanya [424]

Answer:

33i - 12

Step-by-step explanation:

8i - (12 - 4i) + 7 \sqrt{ - 9}   \\  = 8i - 12  + 4i + 7 \sqrt{9  \times ( - 1)}  \\ = 12i - 12 + 7 \times 3 \sqrt{ - 1}  \\ = 12i - 12 + 21i  \:  \: ( \because  \sqrt{ - 1} = i)\\  = 12i + 21i - 12 \\   \therefore \red{ \bold{8i - (12 - 4i) + 7 \sqrt{ - 9} }=  \purple{ \bold{33i - 12}}}

5 0
4 years ago
Harrison ordered 6 cases of pickles for his restaurants. Each case contained p jars of pickles. Harrison delivered an equal numb
natita [175]
6 cases ordered
'p' jars in each case
Total number of jars is    (6 cases) x (p jars/case)  =  6p jars

Split 7 ways, each restaurant gets (1/7) of the total order = 6p/7 jars.

I sure hope 'p' is a multiple of 7, or else Harrison might
need to deal with the number of pickles in each jar.
5 0
3 years ago
Read 2 more answers
Helpp me pleasse im going to cryy please respond asap
vodka [1.7K]

Answer:

4

Step-by-step explanation:

5 0
3 years ago
Find the inverse of f(x) = 2x - 5. The 4 options are in the pic below. PLEASE HELP.
leva [86]

Answer:

The answer is B

Step-by-step explanation:

I hope this helped :)

3 0
3 years ago
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For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth
murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

7 0
3 years ago
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