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3 years ago

Distributed Property Please simplify 5(-x-4)-4 thanks

Mathematics

1 answer:

den301095 [7]3 years ago

5 0

It’ll be -5x - 24

you multiply the 5 by 4 and it’ll be 24, and put the x with the 5 and that’ll be your answer :)

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Your math teacher tells you that the next test is worth 100 points and contains 38 problems. Multiple-choice questions are worth

rusak2 [61]

If we assume that
x isthe number of multiple choice questions, and y is the number of word problems, we can write a system of equations like:
{ x + y = 38
{ 2x + 5y = 100

If we multiply the first equation by -2 we get:
{ -2x-2y = -76
{ 2x + 5y = 100

Now if we add both equations we get only equation with 1 unknown (y) :

3y = 24 ⇒ y = 8

Substituting the calculated value to the first equation we get:

x + 8 = 38 ⇒ x = 30

The solution:
{ x = 30
{ y = 8

means that:
The test had 30 multiple choice questions, and 8 word problems.

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3 years ago

Classify the triangle by it's angels and sides. Explain how you knew which classifications to use. 8, 70 degrees, 11, 45 degrees

anzhelika [568]

The angles degrees are all less than 90 degrees. Therefore the triangle is an acute triangle

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3 years ago

Look at this graph:

Anton [14]

Answer:

3/2

Step-by-step explanation:

slope=rise/run=30/20=3/2

5 0

2 years ago

What is #5 I don’t know the answer.

denpristay [2]

If the axis of symmetry is x=-1, the vertex will have x-coordinate -1.

The point (0, 5) cannot be the vertex. The friend is not correct.

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If the point (1, 5) is on the graph so is the image of that point when it is reflected across the axis of symmetry. That image point is (-3, 5). A parabola that goes through points (1, 5) and (-3, 5) will not go through point (0, 5).

4 0

2 years ago

Consider the surface f (x comma y comma z )f(x,y,z)equals=negative 2 x squared plus 2 y squared minus 3 z squared plus 3 equals

trapecia [35]

Answer:

a) (8,8,-6)

b) 4x+4y+3z = -3

Step-by-step explanation:

The surface is given by the equation

f(x,y,z) = 0 where

$f(x,y,z)=-2x^2+2y^2-3z^2+3$

The gradient of this function is the vector

$(\frac{\partial f}{\partial x},\frac{\partial f}{\partial y},\frac{\partial f}{\partial z})=(-4x,4y,-6z)$

If we evaluate it in the point P = (-2,2,1) we obtain the point

(8,8,-6)

The vectors with their tails at P are of the form

(-2,2,1)-(x,y,z) = (-2-x, 2-y, 1-z)

as they must be orthogonal to the gradient, they must be orthogonal to the vector (8,8,6) so their inner product is 0

$(-2-x,2-y,1-z)\cdot(8,8,6)=0\Rightarrow -16-8x+16-8y+6-6z=0\Rightarrow 4x+4y+3z=-3$

and the equation of the desired plane is

4x+4y+3z = -3

3 0

3 years ago