Answer: root t(5)/19300
Explanation:
P(t) = 19300(5)^t
P-1(t) = root t(5)/19300
Answer:
5
Step-by-step explanation:
in each sample there were 50 students, in a group of 800 there would be 16 samples taken, if you divide the total amount of kids with Novemeber birthdays, 80 by the amount of samples, 16, youll learn that in each sample there are 5 students to have a birthday in november within each sample, hope this helps.
Answer:
0.44
Step-by-step explanation:
Given the estimated logistic regression model on risk of having squamous cell carcinoma
-4.84 + 4.6*(SMOKER)
SMOKER = 0 (non-smoker) ; 1 (SMOKER)
What is the predicted probability of a smoker having squamous cell carcinoma?
exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))
SMOKER = 1
exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)
exp^(-0.24) / (1 + exp^(-0.24))
0.7866278 / 1.7866278
= 0.4402863
= 0.44
