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aalyn [17]
3 years ago
6

Tubulovillous adenoma with high grade dysplasia

Biology
1 answer:
Sergeu [11.5K]3 years ago
4 0

Explanation:

Adenomatous genes are most often found among neoplastic genes and are the target of 2/3 of all colon members. The factors of risks associated with its onset include advanced age, sedentary lifestyle, male gender and increased BMI / abdominal fat. Dysplasia gives it the potential for malignancy, constituting the precursors of most, however, only 5% of adenomas evolve to carcinoma by a process that runs from 7 to 10 years, with the greater risk of progression for advanced adenomas. Adenomatous polyps can be classified into 3 subtypes based on epithelial architecture:

Tubular adenoma: represent about 80% of all adenomas and are characterized by the presence of tubular glands in at least less than 75% of the architecture.

Villous adenoma: account for 5 to 15% of all adenomas and have glands with villous projections in at least 75% of its architecture.

Tubulovillous adenoma: correspond to 5 to 15% of adenomas and has mixed histology with less than 75% of both types of architectures.

High-grade dysplasia is characterized by a complex architecture where there are grouping and glandular irregularity as well as a cribriform pattern and cytological atypia, with loss of nuclear polarity, enlarged nuclei with nucleoli, atypical mitoses, and prominent apoptosis. The high-grade dysplasia has a higher risk of developing for carcinoma

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Answer:

a. S represents allele for short hair while s represents allele for long hair.

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Explanation:

This question involves a single gene coding for hair length in guinea pigs. The allele for short hair (S) is dominant over the allele for long hair (s).

a. Letter "S" will represent the allele for short hair while letter "s" will represent the allele for long hair.

b. According to this question, a heterozygous male is crossed with a long-haired female. The genotype of the male guinea pig is "Ss" while that of the female is "ss". (see attachment for the punnet square)

c. The possible genotypes of the offsprings in this cross are: Ss and ss, each carrying 50% each as they are produced in a ½ Ss: ½ ss.

d. Since 50% of the offsprings will be both short haired and long haired, If they have six babies, 3 of them will be short-haired while 3 of them will also be long-haired.

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However, we know Petri Dishes have nutrients to stimulate cell growth, and those resources are not unlimited therefore we can only attest that a large portion of the nutrients have been consumed and starved some of the cells thus causing a population decrease

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Explanation:

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