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4 years ago

AD¯¯¯¯¯ , BD¯¯¯¯¯ , and CD¯¯¯¯¯ are angle bisectors of the sides of △ABC . BE=12 m and BD=20 m

Mathematics

1 answer:

evablogger [386]4 years ago

5 0

Since triangle BDE is right, we can check it for special rules: BD is hypotenuse = 20, and BE = 12, both divisible by 4: get 5 and 3... so it's a 3-4-5 special right triangle, the 4×4 = 16 m for side DE.
Since AD bisects angle A, I think then side DG should be congruent with DG. So then
DG = 16 m

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Step-by-step explanation:

$a^{2} + b^{2} = c^{2}$

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3 years ago

AD¯¯¯¯¯ ​ , BD¯¯¯¯¯ , and CD¯¯¯¯¯ are angle bisectors of the sides of △ABC . BE=12 m and BD=20 m

AD¯¯¯¯¯ , BD¯¯¯¯¯ , and CD¯¯¯¯¯ are angle bisectors of the sides of △ABC . BE=12 m and BD=20 m