Answer:
(w^2 - 4w + 16)
Step-by-step explanation:
Note that w^3 +64 is the sum of two perfect cubes, which are (w)^3 and (4)^3. The corresponding factors are (w + 4)(w^2 - 4w + 16).
Therefore,
(w^3 +64)/(4+ w) reduces as follows:
(w^3 +64)/(4+ w) (4 + w)(w^2 - 4w + 16)
--------------------------- = --------------------------------- = (w^2 - 4w + 16)
4 + w 4 + w
Answer:
d. 944 mm^3
Step-by-step explanation:
The area of a circle is given by ...
A = πr² . . . . . where r is the radius, half the diameter
The area of a circle with diameter 9 mm is ...
A = π(4.5 mm)² = 20.25π mm²
The area of the semi-circular end of the prism is half this value, or ...
semicircle area = (1/2)(20.25π mm²) = 10.125π mm² ≈ 31.809 mm²
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The area of the rectangular portion of the end of the prism is the product of its width and height:
A = wh = (9 mm)(6 mm) = 54 mm²
Then the base area of the prism is ...
base area = rectangle area + semicircle area
= (54 mm²) +(31.809 mm²) = 85.809 mm²
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This base area multiplied by the 11 mm length of the prism gives its volume:
V = Bh = (85.809 mm²)(11 mm) ≈ 944 mm³
The volume of the composite figure is about 944 mm³.
Answer:
when sketching the curves of functions.
Step-by-step explanation:
There is a wide range of graph that contain asymptotes and that includes rational functions, hyperbolic functions, tangent curves, and more. Asymptotes are important guides when sketching the curves of functions. This is why it’s important that we know the properties, general forms, and graphs of each of these asymptotes.
There are 27 & 1/3 pencils in each box. Each student will get 3 pencils per year. There will be 16 pencils left over.
