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Naily [24]
3 years ago
8

Solve the following equation. Then place the correct number in the box provided. x/9 = 1

Mathematics
2 answers:
Alchen [17]3 years ago
6 0

\frac{x}{9}  = 1 \\  \\ 1. \: x = 1 \times 9 \\  \\ 2. \: x = 9

BARSIC [14]3 years ago
3 0

First, we need to isolate the variable x.

To isolate x, we simply need to multiply both sides by 9, which would result in x = 9

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A car has 15 gallons of gas in its tank. The car travels 35 miles per gallon of gas. It uses 1/35 of gas to go 1 mile. How much
3241004551 [841]

Answer:

um......I think 2 figure it out....

Step-by-step explanation:

A car has 15 gallons of gas in its tank. The car travels 35 miles per gallon of gas. It uses 1/35 of gas to go 1 mile.

6 0
3 years ago
A tube is being stretched while maintaining its cylindrical shape. The height is increasing at the rate of 2 millimeters per sec
hoa [83]

Answer:

V = πr²h

S=2πrh

h= 2/3 millimeters

new height= 8/3 millimeters

S= 8π  millimeters square

New surface area = 32π  millimeters square

Step-by-step explanation:

The volume of the cylinder is given by V = πr²h   where r is the radius and h is the height.

The surface area of the cylinder is given by  S= 2πrh + 2πr²

Where πr² gives the area of the base and 2πr² gives the area of the top and bottom surfaces. The surface area S of a cylinder, not including the top and bottom of the cylinder, is therefore S=2πrh.

V = πr²h

96π= π (6*6) (h+2)

96 = 36 (h+2)

96/36= h+2

h= 96/36-2

h= 96-72/36

h= 24/36

h= 4/6

h= 2/3 millimeters

New height

h + 2= 2/3 + 2

= 2+6/3= 8/3 millimeters

Now S =2πrh

S = 2π(6) (2/3)

S= 8π  millimeters square

New Surface area

S = 2π(6) (8/3)

S= 32π  millimeters square

6 0
3 years ago
Write the differential equation model that fits the given description. (a) The rate of change of the volume of a snowball (due t
miskamm [114]

Answer:

a) he rate of change of the volume of a snowball (due to melting) is proportional to the square of the volume at time t. Initially, the snowball has a volume of 900 cm3

\frac{dV(t)}{dT} = A*V(t)^{2} \\ and V(0) = 900cm^{3}

where A is a real constant, it appears because it says that the change i volume (dV/dt) is "proportional" to V(t)^{2}. Furthermore, we should assume that A is a negative number, because the volume of the snowball will decrease as the time pasese by.

(b) For an insect moving along some path, the velocity at time t is proportional to the square root of its position.

\frac{dr(t)}{dt}  = B*\sqrt{r(t)}

Here again appears a constant B for the "proportional" part. And i wrote the velocity as \frac{dr(t)}{dt} "the rate of change of the position with respect to te time".

7 0
3 years ago
Find the area of this circle.
SashulF [63]

Answer:

not sure man... goodluck tho

3 0
3 years ago
Read 2 more answers
The circle shows the radius of 12mm what is the circumference
gulaghasi [49]

Answer:

24π or about 75.4 mm

Step-by-step explanation:

The circumference of a circle is denoted by C = 2πr, where r is the radius.

Here, we see that r = 12, so plugging this in:

C = 2πr

C = 2π * 12 = 24π ≈ 75.4 mm

The answer is thus 24π or about 75.4 mm.

<em>~ an aesthetics lover</em>

4 0
3 years ago
Read 2 more answers
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