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3 years ago

Solve the following equation. Then place the correct number in the box provided. x/9 = 1

Mathematics

2 answers:

Alchen [17]3 years ago

6 0

$\frac{x}{9} = 1 \\ \\ 1. \: x = 1 \times 9 \\ \\ 2. \: x = 9$

BARSIC [14]3 years ago

3 0

First, we need to isolate the variable x.

To isolate x, we simply need to multiply both sides by 9, which would result in x = 9

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Givin (2, 4) and 6, 12), what is The slope of the line between these two points?

IgorLugansk [536]

Answer:

m=4 or slope =4

Step-by-step explanation: $m=\frac{y2-y1}{x2-x1\\}$

so $m=\frac{12-4}{6-2}$ which is the same as 8/2. So all in all the slope is 4.

5 0

3 years ago

3-7= 4-6= 3+-6= 4--1= -5+-5= -3+5= -4-6=

kipiarov [429]

Answer:

Answers are below

Step-by-step explanation:

3 - 7 = -4

4 - 6 = -2

3 + -6 = -3

4 - - 1 = 5

-5 + -5 = -10

-3 + 5 = 2

-4 -6 = -10

Hope this helps!!

4 0

4 years ago

1 point

WARRIOR [948]

59 is an outlier it's not in the 70s

8 0

3 years ago

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

3 years ago

Consider the standard form equation 2x-Ry=30. What value of R causes the graph to have a y-intercept of 5?

DochEvi [55]

Answer:

R = 6

Step-by-step explanation:

Given the equation of the line is 2x - Ry = 30

We know that the equation of a line with a as x-intercept and b as y-intercept is $\frac{x}{a} +\frac{y}{b} =1$

Now convert the above given line to the standard form

Divide the line by 30 we get

$\frac{2x}{30}-\frac{Ry}{30} =\frac{30}{30}$

$\frac{x}{15} -\frac{y}{\frac{30}{R} } =1$

Here the y-intercept is 30/R

Given y-intercept = 5

$\frac{30}{R} =5$

R = 6

4 0

3 years ago