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3 years ago

8

what is the approximate percent increase when the population of a town increases from 12089 to 15025? round the amounts to the n

earest ten thousand.

2 answers:

fenix001 [56]3 years ago

8 0

15025-12089 = 2936 2936/12089 = .2429 .2429 * 100 = 24.29% or Approx 24 %

bulgar [2K]3 years ago

6 0

The rate of increase is
$\frac{15025}{12089}\approx1.242865$

The percent of increase is then
$(1.242865-1)*100\%=0.242865*100\%=24.2865\%$

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A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and

IRINA_888 [86]

Answer:

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<u>Step-by-step explanation</u>:

<u><em>Explanation</em></u>:-

Given mean of the Population 'μ ' = 51 months

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Let 'X' be the random variable of Normal distribution

<em>Let 'X' = 73</em>

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<em>Let 'X' = 84</em>

<em></em> $Z = \frac{84-51}{11} = 3$ <em></em>

<em>The approximate percentage of cars that remain in service between 73 and 84 months</em>

<em>P( 73 < x < 84 ) = P( 2 < Z < 3)</em>

<em> = P( Z<3) - P( Z <2)</em>

<em> = 0.5 + A(3) - ( 0.5 + A(2))</em>

<em> = A(3) - A( 2)</em>

<em> = 0.49865 - 0.4772 ( From Normal table)</em>

<em> = 0.02145</em>

<em> P( 73 < x < 84 ) = 0.02145</em>

<em>The approximate percentage of cars that remain in service between 73 and 84 months</em>

<em>P( 73 < x < 84 ) = 0.02145 = 2.1 %</em>

7 0

3 years ago

Whoever can help me with my math i will mark brainliest

mezya [45]

Answer:

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Step-by-step explanation:

5 0

2 years ago

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A statue is mounted on top of a 21 foot hill. From the base of the hill to where you are standing is 57feet and the statue subte

AleksandrR [38]

Please find the attached diagram for a better understanding of the question.

As we can see from the diagram,

RQ = 21 feet = height of the hill

PQ = 57 feet = Distance between you and the base of the hill

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$\angle SPR$ =Angle subtended by the statue to where you are standing.

$\angle x=\angle RPQ$ = which is unknown.

Let us begin solving now. The first step is to find the angle $\angle x$ which can be found by using the following trigonometric ratio in $\Delta PQR$ :

$tan(x)=\frac{RQ}{PQ} =\frac{21}{57}$

Which gives $\angle x$ to be:

$\angle x=tan^{-1}(\frac{21}{57})\approx20.22^{0}$

Now, we know that $\angle x$ and $\angle SPR$ can be added to give us the complete angle $\angle SPQ$ in the right triangle $\Delta SPQ$ .

We can again use the tan trigonometric ratio in $\Delta SPQ$ to solve for the height of the statue, h.

This can be done as:

$tan(\angle SPQ)=\frac{SQ}{PQ}$

$tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}$

$tan(27.32^0)=\frac{h+21}{57}$

$\therefore h+21=57tan(27.32^0)$

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3 0

3 years ago

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madreJ [45]

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2 years ago

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Help pls... 20 points

jok3333 [9.3K]

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3 years ago