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arlik [135]
2 years ago
6

The vertices of rhombus DEFG are D(1, 4), E(4, 0), F(1, –4), and G(–2, 0).

Mathematics
2 answers:
musickatia [10]2 years ago
7 0
20 units im shure i took the test'

nirvana33 [79]2 years ago
4 0

Answer: Perimeter of the rhombus is 20 units.

Step-by-step explanation:

Since we have given that

The vertices of rhombus DEFG whose vertices are as follows:

D(1, 4), E(4, 0), F(1, –4), and G(–2, 0)

As shown in the figure below:

Distance between DE is given by

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\D=\sqrt{(4-1)^2+(0-4)^2}\\\\D=\sqrt{3^2+4^2}\\\\D=\sqrt{9+16}\\\\D=\sqrt{25}\\\\D=5\ units

Since it is a rhombus all sides will be equal to each other,

So, Perimeter of rhombus is given by

4\times Side\\\\=4\times 5\\\\=20\ units

Hence, Perimeter of the rhombus is 20 units.


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Now move to point P. Walk 3 spaces to the right until you land on segment AC. This shows that the height of the triangle is 3 when the base is AC = 7.

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<em />

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