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3 years ago

Solve each division problem

Mathematics

1 answer:

bixtya [17]3 years ago

3 0

What are the divisions problema/problems

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Find the peremiter of triangle ABC

cricket20 [7]

Answer:

Step-by-step explanation:

if AB : BC : AC is 3 : 4 : 2 and BC = 8 then AB = 6 and AC = 4

To calculate the perimeter of the triangle we add all side lengths up

4 + 6 + 8 = 18

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3 years ago

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Vesnalui [34]

Answer:

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Step-by-step explanation:

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3 years ago

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If 3, x, y, -9 are in A.P, find the values of x and y.

Serggg [28]

Answer:

x = -1
y = -5

Step-by-step explanation:

The common difference (d) can be found using the first and 4th terms:

a1 = 3

a4 = a1 +d(4 -1)

-9 = 3 +3d . . . . . simplify

-3 = 1 + d . . . . . . divide by 3

-4 = d . . . . . . . . . subtract 1

Then ...

x = a1 + d = 3 -4 = -1

y = x + d = -1 -4 = -5

The values of x and y are -1 and -5, respectively.

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3 years ago

A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30 What score is necessary to reach

nlexa [21]

Answer:

A score of 150.25 is necessary to reach the 75th percentile.

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.

This means that $\mu = 130, \sigma = 30$