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Murljashka [212]
3 years ago
11

Simplify the expression to a form in which 2 is raised to a single integer power. fraction numerator open parentheses 2 to the p

ower of 10 close parentheses cubed 2 to the power of short dash 10 end exponent over denominator 2 to the power of short dash 7 end exponent end fraction
Mathematics
1 answer:
anzhelika [568]3 years ago
5 0

Answer:

2^27

Step-by-step explanation:

Given the following expression:

[(2^10)^3 x (2^-10)] ÷ 2^-7

This can be easily simplified. Let us simplify the numerator first. To do that, we have

(2^10)^3 making use of the power rule of indices that says:

(A^a)^b = A^ab where a and b are powers, we have:

2^(10x3) = 2^30

Therefore the numerator becomes:

2^30 x 2^-10. Also making use of the multiplication rule that says:

A^a x A^b = A^(a + b), we have

2^30 x 2^-10 = 2^(30 – 10) = 2^20.

Now we have:

(2^20) ÷ (2^-7)

To simplify this, we need the division rule of indices which says:

A^a ÷ A^b = A^(a – b)

Therefore we have:

(2^20) ÷ (2^-7) = 2^[20 – (–7)] = 2^(20+7) = 2^27

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What are 26 divide by 4,340
mart [117]
\frac { 26 }{ 4,340 } \\ \\ =\frac { 26 }{ 4\cdot { 10 }^{ 3 }+3\cdot { 10 }^{ 2 }+4\cdot { 10 }^{ 1 } } \\ \\ =\frac { 26 }{ 10\left( 4\cdot { 10 }^{ 2 }+3\cdot { 10 }^{ 1 }+4 \right)  } \\ \\ =\frac { 2\cdot 13 }{ 2\cdot 5\left( 4\cdot { 10 }^{ 2 }+3\cdot { 10 }^{ 1 }+4 \right)  } \\ \\ =\frac { 13 }{ 5\left( 4\cdot { 10 }^{ 2 }+3\cdot { 10 }^{ 1 }+4 \right)  }

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