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Natasha2012 [34]

3 years ago

13

if a person puts 1 cent in a piggy bank in the first day, 2 cents on the second day, 3 cents on the third day, and so on, how mu

ch money will be in the bank after 50 days?

2 answers:

MariettaO [177]3 years ago

6 0

The answer would be: $8.20

sukhopar [10]3 years ago

5 0

well all of tose added together get you to 1245 cents

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Factor.<br> x*2+11x+28<br> please give me the answer

zvonat [6]

Answer:

(x+4)(x+11)

Step-by-step explanation:

x^2+11x+28

What two numbers multiply to 28 and add to 11

4*7 =28

4+11

(x+4)(x+11)

7 0

3 years ago

Read 2 more answers

What acronym is used for sine , cosine and tangent

sergejj [24]

Answer:

SOHCAHTOA.

Step-by-step explanation:

acronym is an abbreviation formed from the initial letters of other words and pronounced as a word

The acronym for sin cosine and tangent is

SOHCAHTOA

Sine =Opposite over Hypotenuse

Cosine= Adjacent over Hypotenuse

Tangent= Opposite over Adjacent

8 0

3 years ago

What is 2 X (6+ 2 + 8) -4

VladimirAG [237]

Answer:

The correct answer is 32x - 4

Step-by-step explanation:

1) Simplify 6 + 2 to 8.

$2x(8 + 8) - 4$

2) Simplify 8 + 8 to 16.

$2x \times 16 - 4$

3) Simplify 2x × 16 to 32x.

$32x - 4$

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>32x</u><u> </u><u>-</u><u> </u><u>4</u>.

4 0

3 years ago

If a+b=9 and ab=18,find the value of a and b.

Blizzard [7]

Answer:

Given:

a + b = 9

=> a = 9 - b

Given:

a x b = 18

=> (9 - b) x b = 18

=> 9b - b^2 = 18

=> b^2 - 9b + 18 = 0

=> (b - 3)(b - 6) = 0

=> b = 3 => a = 6

=> b = 6 => a = 3

Hope this helps

:)

3 0

3 years ago

Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is

Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since, its head is twice as likely to occur as its tail.

$p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}$

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n = 3

$p=\dfrac{2}{3}$

$q=\dfrac{1}{3}$

Now,

$P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222$

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

$P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292$

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

$P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111$

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0

3 years ago