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malfutka [58]
3 years ago
10

As a ray of light becomes brighter, its corresponding light wave, shown here, will increase in amplitude, making it look MOST li

ke which wave?
Physics
2 answers:
grandymaker [24]3 years ago
6 0

Answer:

the answer is C

Explanation:

i did the usatestprep

andreev551 [17]3 years ago
5 0

Answer:

c usa test prep

Explanation:

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A non-reflective coating that has a thickness of 198 nm (n = 1.45) is deposited on top of a substrate of glass (n = 1.50). What
spin [16.1K]

Answer:

The  wavelength is \lambda_ 1 =  574.2 nm

Explanation:

From the question we are told that  

      The  thickness is t =  198 nm  =  198 *10^{-9 }\ m

      The refractive  index of the non-reflective coating is  n_m  =  1.45  

       The  refractive  index of glass is n_g  = 1.50

       

Generally the condition for  destructive  interference is mathematically represented as

            2 *  n_m *  t  *  cos (\theta) =  n  *  \lambda

Where \thata \theta is the angle of refraction which is  0° when the light is strongly transmitted

    and  n is the order maximum interference

        so  

             \lambda = \frac{2 *  n *  t  *  cos (\theta )}{n}

at the point n =  1  

           \lambda _1 = \frac{2 *  1.45  *  198*10^{-9}  *  cos (0 )}{1}

           \lambda_1  = 574.2 *10^{-9}

          \lambda_1  = 574.2 nm

at  n =2  

         \lambda _2  =  \frac{\lambda _1 }{2}

         \lambda _2  =  \frac{574.2*10^{-9} }{2}

         \lambda _2  =  2.87 1 *10^{-9} \ m

         \lambda _2  =  287. 1  nm

Now we know that the wavelength range of visible light is  between

           390 \ nm \to  700 \ nm

   So the wavelength of visible light that is been transmitted is  

          \lambda_ 1 =  574.2 nm

           

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4 years ago
The earth exerts a gravitational force on the moon. the moon exerts a gravitational force on the earth. how do the magnitudes of
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The forces are the same like the third law of Newton states.I think
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The electrons in a particle beam each have a kinetic energy K. What is the magnitude of the electric field that will stop these
harina [27]

Answer:

Electric field magnitude

E = K/qd

Where

K = kinetic energy of electron

d = electron distance

q = charge

Explanation:

Given the relationship between workdone and energy

Work-energy theorem:

Net workdone = Energy change

W = ∆E

In this case

W = ∆K.E

And,

∆K.E = K(final) - K(initial)

To stop the kinetic energy | K(final) = 0

K(initial) = K (given)

∆K.E = 0 - K = -K

Let the electric force on the electron has magnitude F.

And

W = -Fd = ∆K.E = -K

-Fd = -K

F = K/d .....1

The magnitude of the electric field E that can stop these electron in a distance d:

E = F/q ......2

Where q is the charge on electron.

substituting equation 1 to 2

E = (K/d)/q = K/qd

E = K/qd

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What creates the changes in step 1,2,3 of the nitrogen cycle
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1-fixation ( Bacteria Converts nitrogen to ammonium so plants can use it )
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