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Lelu [443]
3 years ago
12

Most ocean waves obtain their energy and motion from _____. the moon's gravitational attraction the sun plate movement the wind

Physics
1 answer:
IrinaVladis [17]3 years ago
3 0
Hello!

Most ocean waves obtain their energy and motion from the wind.

Ocean waves are surface waves that move across the surface of the ocean. When wind touches the surface of the water, there is friction in the contact zone. This friction causes a drag effect, that makes wrinkles on the surface of the water. As the wrinkles get bigger, they transform into full-blown waves, and the taller the wave, the more energy it can extract from the wind, making them even bigger and to move longer distances. 

Have a nice day!


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Scientists in a test lab are testing the hardness of a surface before constructing a building. Calculations indicate that the en
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A portable x-ray unit has a step-up transformer. The 120 V input is transformed to the 100 kV output needed by the x-ray tube. T
slega [8]

Answer:

 N_s\approx41667 \hspace{3}lo ops

Explanation:

In an ideal transformer, the ratio of the voltages is proportional to the ratio of the number of turns of the windings. In this way:

\frac{V_p}{V_s} =\frac{N_p}{N_s} \\\\Where:\\\\V_p=Primary\hspace{3} Voltage\\V_s=V_p=Secondary\hspace{3} Voltage\\N_p=Number\hspace{3} of\hspace{3} Primary\hspace{3} Windings\\N_s=Number\hspace{3} of\hspace{3} Secondary\hspace{3} Windings

In this case:

V_p=120V\\V_s=100kV=100000V\\N_p=50

Therefore, using the previous equation and the data provided, let's solve for N_s :

N_s=\frac{N_p V_s}{V_p} =\frac{(50)(100000)}{120} =\frac{125000}{3} \approx41667\hspace{3}loo ps

Hence, the number of loops in the secondary is approximately 41667.

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4 years ago
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While taking off from an aircraft carrier, a jet starting from rest accelerates uniformly to a final speed of 40. meters per sec
mariarad [96]

The acceleration of the jet is 11.4 m/s^2

Explanation:

Since the jet motion is a uniformly accelerated motion (=constant acceleration), we can use the following suvat equation:

v^2-u^2=2as

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v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the jet in this problem, we have

u = 0 (it starts from rest)

v = 40 m/s (final velocity)

s = 70 m (length of the runway)

Solving for a, we find the acceleration:

a=\frac{v-u}{t}=\frac{40^2-0}{2(70)}=11.4 m/s^2

Learn more about acceleration:

brainly.com/question/9527152

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