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3 years ago

How do you find an inequality on a graph ?

1 answer:

3 0

There are three steps:<span>Rearrange the equation so "y" is on the left and everything else on the right.Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)<span>Shade above the line for a "greater than" (y> or y≥) or below the line for a "less than" (y< or y≤).</span></span>

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Kenzie makes $12.50 per hour. She works 20 hours per week. Find: a. Her weekly pay b. Her monthly pay c. Her yearly pay d. Her w

NISA [10]

Answer:

a=250

b=?

c=?

Step-by-step explanation:

b= what month, how many days

c=?

7 0

3 years ago

The graph shows the height (h), in feet, of a basketball t seconds after it is shot. Projectile motion formula: h(t) = -16t2 + v

Harlamova29_29 [7]

Answer:

$\boxed{h(t)=-16t^2+24t+6}$

<h2>Step-by-step explanation: </h2><h2 /><h3>From the statement of the problem we know: </h3>

The graph shows the height (h), in feet, of a basketball t seconds after it is shot. Projectile motion formula:

$h(t)=-16t^2+vt+h_{0}$

$v$ = initial vertical velocity of the ball in feet per second

$h_{0}$ = initial height of the ball in feet Complete the quadratic equation that models the situation.

<h3>From the graph we know: </h3>

$h(0)=6 \\ \\ \therefore 6=-16(0)^2+v(0)+h_{0} \\ \\ \therefore h_{0}=6$

For a quadratic function:

$f(x)=ax^2+bx+c \\ \\ \\ The \ vertex \ is: \\ \\ V(-\frac{b}{2a},f(-\frac{b}{2a})) \\ \\ Since: \\ \\ h(t)=-16t^2+vt+6 \ then: \\ \\ a=-16 \\ b=v \\ c=h_{0}=6 \\ \\ So: \\ \\ -\frac{b}{2a}=-\frac{v}{2(-16)}=0.75 \\ \\ \frac{v}{32}=0.75 \\ \\ \therefore v=32(0.75) \ \therefore v=24$

Finally:

$\boxed{h(t)=-16t^2+24t+6}$

6 0

3 years ago

Read 2 more answers

Explicit equation for the sequence

Jlenok [28]

Step-by-step explanation:

when we get the common ratio that must be equal

r=6/2=18/6=54/18=3 equal

So it is geometric

By using this equation:

a(n)=a(1)*r^(n-1)

and we have a(1)=2 , r=3

Explicit rule: a(n)=2*(3)^(n-1)

hope this helps

3 0

3 years ago

Write the equation of the line in y=Mx+b from (0,0), (10,2)

Nana76 [90]

Gradient, m=(2-0)/(10-0)=1/5
At (10,2), 2=1/5(10)+b
b=0
Equation: y=1/5 x
Hope this can help.

6 0

3 years ago

The graph of a quadratic function has x intercepts at -3 and 5/2, and y intercept at 10. Give the function.

sesenic [268]

Answer:

f(x) = -4/3x² -2/3x +10

Step-by-step explanation:

The quadratic regression function of a graphing calculator or spreadsheet can determine the equation for you.

___

Or, you can determine it yourself.

The equation can be written in the form ...

f(x) = a(x +3)(x -5/2) . . . . . . . using the given x-intercepts

for some value of "a"

For x = 0, this must match the y-intercept.

f(0) = a(0 +3)(0 -5/2) = 10

-15/2·a = 10

a = -20/15 = -4/3

So, the function can be written as ...

f(x) = (-4/3)(x +3)(x -5/2)

f(x) = -4/3x² -2/3x +10

7 0

3 years ago

Read 2 more answers