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Nuetrik [128]
3 years ago
9

Solve the Inequality: 4+6x≤x+6x​

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
5 0
4+6x ≤ x+6x

Subtract 6x from both sides

4 ≤ x
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I need help please & thank you
White raven [17]

3(2c+d)-4(c-d)+d^2

c=1 , d=3

Use the substitution method

3(2*1+3)-4(1-3)+3^2

Multiply the brackets

3(2+3)-4+12+9

6+9-4+12+9

15-4+12+9

11+21

=32

Answer: 32

5 0
3 years ago
Read 2 more answers
What does 3 (2x - 4) = 8x 14 equal?
jeka57 [31]
6x - 12 = 8x + 14
2x = - 26
x = - 13
5 0
3 years ago
Y=x²-6x+8 what is y when x is 0?
jarptica [38.1K]

Answer:

The value of y is 8.

Step-by-step explanation:

In order to find the value of y, you have to put in x = 0 into the equation :

y =  {x}^{2}  - 6x + 8

Let x = 0,

y =  {0}^{2}  - 6(0) + 8

y = 8

6 0
3 years ago
How many ways can eight letters be arranged into groups of five where order matters and the first two letters are already chosen
fenix001 [56]

Answer:

120

Step-by-step explanation:

Since we're dealing with a problem where the order matters and the first two letters are already chosen we need to subtract the number of letters and the number of available slots per group.

We use the permutation formula to find the answer, but before that let's check values.

n = 8

k = 5

Now since there are two letters already chosen we have to deduct two from both the value of n and k.

n = 6

k = 3

Now we can use the permutation formula:

_{n}P_{k}=\dfrac{n!}{(n-k)!}

_{6}P_{3}=\dfrac{6!}{6-3)!}

_{6}P_{3}=\dfrac{6!}{3!}

_{6}P_{3}=\dfrac{6*5*4*3*2*1}{3*2*1}

The 3*2*1 cancels out and leaves us with:

_{6}P_{3}=6*5*4

_{6}P_{3}=120

So there are 120 possible ways to arrange eight letters into groups of five where order matters and the first two letters are already chosen.

6 0
3 years ago
Read 2 more answers
Use the divisibility rules to determine which of the following numbers 504 is divisible by.
Reika [66]

Answer:

504 is divisible by 2, 3, and 7. It is not divisble by 5 or 11

Step-by-step explanation:

C'mon. Use a calcultor.

3 0
3 years ago
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