<span>The square root of -16 is an imaginary number and a complex number. Sqrt(-16)=4i. We use the i to indicate that the number is imaginary since there is no number that can be multiplied by itself to get a negative number (a negative times a negative is a positive, and a positive times a positive is also a positive). So the use of i tells you immediately that it's an imaginary number. You can tell the number is complex because it has both a real and an imaginary part and could be written in the form a+bi, where a is a real number and bi is an imaginary number. In this specific case, the real part (a) is 0 and the imaginary part (bi) is 4i.</span>
Answer:
1 and 1
Step-by-step explanation:
Answer:
![3v^2\left(5v^6-7v^3\right)=15v^8-21v^5](https://tex.z-dn.net/?f=3v%5E2%5Cleft%285v%5E6-7v%5E3%5Cright%29%3D15v%5E8-21v%5E5)
Step-by-step explanation:
Given the expression
![3v^2\left(5v^6-7v^3\right)](https://tex.z-dn.net/?f=3v%5E2%5Cleft%285v%5E6-7v%5E3%5Cright%29)
Apply the distributive law
![a\left(b-c\right)=ab-ac](https://tex.z-dn.net/?f=a%5Cleft%28b-c%5Cright%29%3Dab-ac)
![a=3v^2,\:b=5v^6,\:c=7v^3](https://tex.z-dn.net/?f=a%3D3v%5E2%2C%5C%3Ab%3D5v%5E6%2C%5C%3Ac%3D7v%5E3)
![=3v^2\cdot \:5v^6-3v^2\cdot \:7v^3](https://tex.z-dn.net/?f=%3D3v%5E2%5Ccdot%20%5C%3A5v%5E6-3v%5E2%5Ccdot%20%5C%3A7v%5E3)
![=3\cdot \:5v^6v^2-3\cdot \:7v^3v^2](https://tex.z-dn.net/?f=%3D3%5Ccdot%20%5C%3A5v%5E6v%5E2-3%5Ccdot%20%5C%3A7v%5E3v%5E2)
![=15v^8-21v^5](https://tex.z-dn.net/?f=%3D15v%5E8-21v%5E5)
Thus, we conclude that
![3v^2\left(5v^6-7v^3\right)=15v^8-21v^5](https://tex.z-dn.net/?f=3v%5E2%5Cleft%285v%5E6-7v%5E3%5Cright%29%3D15v%5E8-21v%5E5)
Answer: 25
Step-by-step explanation: