Answer:
The percentage yield of methanol is 78.74%.
Explanation:
Theoretical yield of methanol ;
Moles of hydrogen gas =
Moles of carbon monoxide =
According to reaction ,1 mole of CO reacts with 2 moles of hydrogen gas. Then 0.1786 moles of CO will :
As we can see, that moles of hydrogen gas are in excess and CO are in limiting amount, so amount of methanol will depend upon moles of CO.
According to recation 1 mole of CO gives 1 mole of methanol, then 0.1786 moles of CO will give:
Mass of 0.1786 moles of methanol =
= 0.1786 mol × 32 g/mol = 5.7152 g
Theoretical yield of methanol = 5.7152 g
Experimental yield of methanol = 4.5 g
Percentage yield of methanol:
To calculate the percentage yield , we use the equation:
The percentage yield of methanol is 78.74%.