Answer:
ii) the energy of the electron on the outer shell
iv) the overall size of an orbital
Explanation:
There are four quantum numbers to define the position and energy level of an electron in an atom
a) Principal : The principal quantum number (n) is to know the energy of an electron in an atom and its possible distance from the nucleus.
b) Azimuthal: It refers to the shape of the subshell or orbital of the electron and thus the angular distribution.
c) Magnetic: It refers to the number of orbits and their orientation in the subshell.
d) spin: It refers to the spin of the electron.
Answer is in picture below.
Use 100 grams of the compound:
ω(Cl) = 85.5% ÷ 100%.
ω(Cl) = 0.855; mass percentage of the chlorine in the compound.
m(Cl) = 0.855 · 100 g.
m(Cl) = 85.5 g; mass of chlorine.
m(C) = 100 g - 85.5 g.
m(C) = 14.5 g; mass of carbon.
n(Cl) = m(Cl) ÷ M(Cl).
n(Cl) = 85.5 g ÷ 35.45 g/mol.
n(Cl) = 2.41 mol; amount of chlorine.
n(C) = 14.5 g ÷ 12 g/mol.
n(C) = 1.21 mol; amount of carbon.
n(Cl) : n(C) = 2.41 mol : 1.21 mol = 2 : 1.
This compound is dichlorocarbene CCl₂.
Answer:
It uses sodium nitrate, so that the nitrate group reacts with silver and precipitates as a salt, thus forming silver nitrate
And as for the precipitation of barium, I would use sodium sulfate, since we would use the nitrate group, barium nitrate would form, which is very dangerous and is considered high risk.
Explanation:
All the compounds that we name are reactions where as a product they give salts that are highly complex, where they are solid at room temperature, precipitate and are whitish in color.
These salts so that they precipitate it is important that they are in supersaturation since otherwise they will be in constant dynamism dissolving with the water, since they are soluble in them and the decantation will not be perceived at the naked eye of the human eye.
Answer:
<u>Hey</u><u> </u><u>buddy</u><u>,</u>
Partial pressure of a gas is calculated by <u>Multiplying</u><u> </u><u>the</u><u> </u><u>total</u><u> </u><u>pressure</u><u> </u><u>by</u><u> </u><u>mole</u><u> </u><u>fraction</u><u> </u><u>of</u><u> </u><u>that</u><u> </u><u>gas</u><u>.</u>
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