The mass (in grams) of iron, Fe that can be made from 21.5 g of Fe₂O₃ is 15.04 g
We'll begin by writing the balanced equation for the reaction. This is given below:
2Fe₂O₃ -> 4Fe + 3O₂
- Molar mass of Fe₂O₃ = 159.7 g/mol
- Mass of Fe₂O₃ from the balanced equation = 2 × 159.7 = 319.4 g
- Molar mass of Fe = 55.85 g/mol
- Mass of Fe from the balanced equation = 4 × 55.85 = 223.4 g
From the balanced equation above,
319.4 g of Fe₂O₃ decomposed to produce 223.4 g of Fe
<h3>How to determine the mass of iron, Fe produced</h3>
From the balanced equation above,
319.4 g of Fe₂O₃ decomposed to produce 223.4 g of Fe
Therefore,
21.5 g of Fe₂O₃ will decompose to produce = (21.5 × 223.4) / 319.4 = 15.04 g of Fe
Thus, 15.04 g of Fe were produced.
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The answer is likely to be A
Answer:
The elements in the alkaline earth metals group; beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra), have two electrons in their outer electronic shell.
Explanation:
Wym there is no question or statements.
Answer: 3378.4mL
Explanation:
density of Gasoline = 0.74g/mL.
Volume of gasoline in milliliter = ?
mass of gasoline = 2.5kg
(Since density is in grams per millilitre, convert mass in kilograms to grams)
If 1kg = 1000grams
2.5kg = 2.5 x 1000 = 2500grams
Recall that density is obtained by dividing the mass of a substance by its volume
i.e Density = Mass / Volume
0.74g/mL = 2500grams/Volume
Volume = (2500 grams / 0.74g/mL)
Volume = 3378.4mL
Thus, the volume of gasoline is 3378.4mL
