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alekssr [168]
2 years ago
14

Explain the relationship between the shape of the base of a prism and the number of lateral faces. Use examples to justify your

answer
Mathematics
1 answer:
svetoff [14.1K]2 years ago
4 0

Answer:

thay both are the same shape and size

Step-by-step explanation:

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|-5| – |-2| how do you do this. so you know this is high school work
makvit [3.9K]
=3
The absolute value of any number is ALWAYS positive. Negatives get changed to positives.
5-2=3 
8 0
2 years ago
Read 2 more answers
Zack watered his garden with 1 3/8
victus00 [196]

Answer:

<u>The correct answer is that Zack used 2 7/8 gallons to water his garden on the fifth week.</u>

Step-by-step explanation:

Let's find out the pattern Zack is using to water his garden, this way:

First week =  1 3/8  gallons of water

Second week = 1 3/4 gallons of water = 1 3/8 + 3/8 = 1 6/8 = 1 3/4

Third week = 2 1/8 gallons of water = 1 3/4 + 3/8 = 1 6/8 + 3/8 = 2 1/8

The constant of adding every week is 3/8 gallons, therefore,

Fourth week = 2 1/8 + 3/8 = 2 4/8 = 2 1/2 gallons of water

Fifth week = 2 1/2 + 3/8 = 2 4/8 + 3/8 = 2 7/8 gallons of water

<u>The correct answer is that Zack used 2 7/8 gallons to water his garden on the fifth week.</u>

3 0
3 years ago
3/5 + 1/2 =? ; 1/2 + 3/8 =? ; 1/2 + 2/5=?
slavikrds [6]
3/5+1/2=___
To add them together, convert both fractions so they have the same denominator.
3/5=6/10 and 1/2=5/10
6/10+5/10=11/10, or 1 1/10

1/2+3/8=___
Same for this one- convert both fractions so they have the same denominator.
1/2=4/8 and 3/8 stays the same
4/8+3/8=7/8

1/2+2/5
And again, convert both fractions so they have the same denominator.
1/2=5/10 and 2/5= 4/10
5/10+4/10=9/10

Hope this helps :-)
5 0
3 years ago
Read 2 more answers
Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

8 0
2 years ago
Please answer with clear instructions so that i can apply this to other questions
marishachu [46]

Answer:

1 and - 1

Step-by-step explanation:

The equation of a line passing through the origin is

y = mx ( m is the slope ( gradient ) )

y = x ← is in this form

with gradient m = 1

Parallel lines have equal gradients

Then the gradients of lines parallel to the given line is 1

Given a line with gradient m then the gradient of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{1} = - 1

Then the gradients of lines perpendicular to this line is - 1

4 0
2 years ago
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