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lisabon 2012 [21]
3 years ago
9

A right triangle has sides of length 3, 4, and x. Find x if it is one of the legs

Mathematics
1 answer:
lianna [129]3 years ago
6 0
I think it might be 5, because it is a pythagrum triple
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Each lap around Steven's block is seven eighths of a mile. If Steven ran six
maks197457 [2]

Answer:

10.06 miles

Step-by-step explanation:

Each lap around Steven's block is \frac{7}{8} = 0.875 miles.

If Steven ran six laps last week and five and a half laps this week, then the total number of laps that Steven ran is = (6 + 5\frac{1}{2}) = (6 + 5.5) = 11.5 laps.

Therefore, the number of miles that he ran will be (11.5 × 0.875) = 10.0625 miles ≈ 10.06 miles (Round to two decimal digits) (Answer)

8 0
3 years ago
Sylvia translated the phrase into an algebraic expression and then evaluated it for n=5
frosja888 [35]
The value you should get is 34. I'm assuming n is variable we should use. "the square of a number increased by 9" = "n^2+9" in an algebraic expression. then you plug in. 5^2+9 and then solve. 5^2=25. 25+9=34 
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3 years ago
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Which statement shows the associative property of addition?
abruzzese [7]

Answer:

\displaystyle (18 + 6) + y = 18 + (6 + y)

Step-by-step explanation:

This shows the correct way to use the <em>Associative</em><em> </em><em>Property</em><em> </em>because there are GROUPING SYMBOLS wrapped around UNIQUE parts of each expression, and STILL gets the exact same result.

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8 0
3 years ago
What is the answer for this in square root form
vredina [299]

Answer:

x =  ± sqrt(-49)

or x =  ± 7i

Step-by-step explanation:

x^2 +49 = 0

Subtract 49 from each side

x^2 +49 -49 = 0-49

x^2 = -49

Take the square root of each side

sqrt(x^2) = ± sqrt(-49)

x =  ± sqrt(-49)

We have to complex numbers to solve

x = ± sqrt(-1) sqrt(49)

sqrt(-1) = i

x =  ±i *7

x =  ± 7i

4 0
3 years ago
Please help me i will give BRAINLIEST<br> help
SSSSS [86.1K]

Answer:

A) T and R

B) <SQR or <RQS

C) Q

Step-by-step explanation:

A) The sides of a angle are the end points which are T and R in this case.

B) Angle 2 has S and R and its end points. And the vertex which is Q is always in the middle, so the angle is <SQR and <RQS

7 0
3 years ago
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