Question

Can someone help me with this math problem?

Answer 1

The area of ΔIDK is 32.69 square units.

Solution:

Given data:

ID = 7 and Hypotenuse, KI = 11.67.

Let us first find KD:

Using Pythagoras theorem,

$\text {Base}^{2}+\text {Height}^{2}=\text {Hypotenuse}^{2}$

$ID^2 + KD^2 = KI^2$

$7^2 + KD^2 = (11.67)^2$

$49 + KD^2 = 136.1889$

Subtract 49 from both sides.

$KD^2=87.1889$

Taking square root on both sides, we get

KD = 9.34

Area of the triangle = $\frac{1}{2}\times\text{base}\times\text{height}$

                                $=\frac{1}{2}\times{7}\times{9.34}$

                                = 32.69

The area of ΔIDK is 32.69 square units.