Find the area of the parallelogram, find the area of the triangle, then subtract the triangle's area from the area of the parallelogram.
Area of Parallelogram:
A= base * height
A= 20 in * 10 in
A= 200 in^2
Area of Triangle:
A= 1/2 base * height
A= 1/2 (10 in)(9 in)
A= 1/2 (90)
A= 45 in ^2
Area of Poster Left:
subtract the difference
A= Parallelogram Area - Triangle Area
A= 200 in^2 - 45 in^2
A= 155 in^2
ANSWER: 155 in^2 is the area of the poster board she has left.
Hope this helps! :)
+,-,=,>,<, and many more, lol i gave more than one :P
Answer:
B. po ang answer sa palagay ko lang po
So let's see here...
6:00 A.M. temperature is 33°F.
12:00 P.M temperature increased by 10°F making it 43°F.
3:00 P.M. temperature increased by another 12°F making it 55°F.
At 10:00 P.M it would decrease by 15°F making it 40°F.
The temperature would need to fall (or decrease) by 7°F to reach the original temperature of 33°F
Hope this helped!
Wait how would you even do this?