Answer:
False
Step-by-step explanation:
Lets call the three prime divisors of n p, q, and r, being r the largest, we know:
Now, if
then
So:
Also, for every natural greater than one, we know:
![\sqrt[3]{n}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%3C%5Csqrt%7Bn%7D)
so
![\sqrt[3]{n}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%3C%5Csqrt%7Bn%7D%20%3C%20r)
from which:
![\sqrt[3]{n} < r](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%20%3C%20r)
So, we see, this means the preposition is false, we can find a particular counterexample:
q=2
p=3
p*q = 6
We need to choose a prime greater than 6
r=7
n= 2 * 3 *7 = 42
![\sqrt[3]{42} = 3.4760 < 7](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B42%7D%20%3D%203.4760%20%3C%207)
Answer:
Step-by-step explanation:
find the least common denominator for both fractions then combine them to find:
(5x³ + 4x²) - (6x² - 2x - 9)
-1(6x²) -1(-2x) -1(-9) = -6x² + 2x + 9
5x³ + 4x² - 6x² + 2x + 9
5x³ - 2x² + 2x + 9 Choice D.
We can use proportion to get the result
10 ----------- 5%
x ------------- 100%
Crossmultiply proportion
5*x=10*100
5x=1000 /:5 divide both sides by 5
x=1000:5
x=200 - its the answer
