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Goshia [24]
4 years ago
10

What is 9847.04 rounded to the nearest hundreth

Mathematics
1 answer:
Ainat [17]4 years ago
5 0
It's already rounded to the nearest hundredth. Hundredth's place is the position of the second digit to the right of to the decimal point.
You might be interested in
Reduce 240 in the ratio 2:3​
schepotkina [342]

Answer:

96 , 144

Step-by-step explanation:

Ratio = 2 : 3

2x + 3x = 240

        5x = 240

           x = 240/5

           x = 48

2x = 2*48 = 96

3x = 3*48  = 144

3 0
3 years ago
A coat in London costs £60. The same coat in Dublin costs €105.60. The exchange rate is £1 = €1.65. In which city is the coat ch
Pie

Answer:

The coat is cheaper in London and it is 6.6 euros cheaper than in Dublin

Step-by-step explanation:

Given

Cost of coat in London = £60

Cost of coat in Dublin = €105.60

In order to find where the coat is cheaper, the price should be in same unit

It is also given that

£1 = €1.65

so,

Price of coat in Euro will be:

P = 60 * 1.65 = 99

So the price of coat in London is 99 Euros

Comparing both the prices we see that

Price in London < Price in Dublin

99 < 105.60

The difference in price is:

=105.60-99= 6.6\ Euros

Hence,

The coat is cheaper in London and it is 6.6 euros cheaper than in Dublin

6 0
3 years ago
When finding the multiples of 2, how can I figure out the 6th term? ​
natka813 [3]

Answer:

2×1=2

2×2=4

2×3=6

2×4=8

2×5=10

2×6=12 ==> Answer

8 0
3 years ago
Are my angles correct?
Licemer1 [7]

Answer:

Yes. You are correct.

Step-by-step explanation:

Tan(U) = opposite / adjactent

Tan(U) = 7*√3 / 7

Tan(U) = √3

Just off the top of my head, they look right.

U = Tan-1 (√3)

U = 60

Therefore tan(W) = 90 - 60 = 30

6 0
3 years ago
1. In how many different ways can 5 people be seated at a round table?
Alexeev081 [22]
1. 

Assume the people A, B, C, D and E are sitting in a row.

since there are 5 positions, they can sit in 5*4*3*2*1=120 ways.

consider 1 certain sitting position, for example ABCDE, that is B has A to his right, C to his left. D has C to his right and E to his left. And so on.

the positions 

ABCDE
BCDEA
CDEAB
DEABC
EABCD

while in a row are different positions, in a round table they are the same thing.

(read the letters starting from A, and when the letters finish, continue reading from the beginning of the row. They all read "ABCDE")

This means that any arrangement in a round table, is converted to 5 arrangements in a row.

So there are in total  \frac{5!}{5}=4*3*2*1=24 arrangements of 5 people around a table.

2. check picture.

Consider the case where A is at (2, 2) and B is at (5, 6)

A can move to B through 3 horizontal units to the right, we call them E (for East) and 4 vertical units up, which we call N (for north).

the total path is 7 units.

it can be done in several ways, for example:

ENNNENE (the red path shown in the figure)
NNEEENN (the black path shown in the figure)

In total there are 
\frac{7!}{3!*4!}= \frac{7*6*5*4!}{3!*4!}= \frac{7*6*5}{3!}= 35 paths.

Remark: 7! is the number of arrangements if the letters were different. We divide by 3! because of the 3 E's and 4! because of the 4 N's. 

Another possibility could be A'(3, -5), B'(8,-3).

From A' to B' we go by a total of 5 E and 2 N, so there are 

\frac{7!}{2!*5!}= \frac{7*6*5!}{2!*5!}= \frac{7*6}{2}= 42 paths in total.
there is one more possibility
\frac{7!}{1!(6!)}=7

C.

a) consider the letters {V,E,C,T,O,R}

we can form 6*5*4*3*2*1=720 words, as the first digit can be any of the 6 letters, combined with 5 for the second letter and so on.

b) the difference with a is that we have 5 letters and we have 2 T.

we have in total 5*4*3*2*1=120 arrangements of these letters, if the 2 T's were considered as separate.

consider the arrangements:

T_1RUST_2 and T_2RUST_1.

We read bth as just TRUST, but the permutation formula 5*4*3*2*1 considers these as 2 different.

this is why we need to divide 120 by 2, to get the actual number of words that can be formed. So the number is 60.

Answers:

1) 24

2) 7, 35 or 42. it depends on the positions of A and B, check the solution

3) a-720, b-160
 

8 0
4 years ago
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