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Svetradugi [14.3K]
3 years ago
5

The concentration C (in mg/cc) of a drug in a patient's bloodstream is related to the time t (in hours) after injection in such

a way that as t changes from 0 to 12, C changes from 0.7 to 0.1. Find the average rate of change of C with respect to t.
I have a calculus question similar to this one and I am unsure of how to begin working on this problem.
Mathematics
1 answer:
valkas [14]3 years ago
5 0

Answer: -0.05 mg/cc*h

Step-by-step explanation:

Here we have the relation:

ConcentrationVsTime.

If we want to find the average rate of change, we can find the slope of a line that passes through the extremes of each interval: (tmin, Cmin) and (tmax, Cmax)

The interval for the time is:

0h to 12h.

The interval for the concentration is:

0.7 mg/cc to 0.1mg/cc.

Then we can use the points:

(0h, 0.7mg/cc) and (12h, 0.1mg/cc)

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1).

Then in this case the slope (or rate of change) is:

a = (0.1mg/cc - 0.7mg/cc)/(12h - 0h) = (-0.6mm/cc)/12h = -0.05 mg/cc*h

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Help lol the question is on the picture please help!
valina [46]

here u go, remember the ratio

7 0
3 years ago
The Expression 4x^2-p(x)+7 leaves a remainder of -2 when divided by (x-3) find the value of p
Romashka-Z-Leto [24]

Answer:

(c)  For p = 15,  4x^2-p(x)+7 leaves a remainder of -2 when divided by (x-3).

Step-by-step explanation:

Here,  The dividend expression is  4x^2-p(x)+7 = E(x)

The Divisor = (x-3)

Remainder  = -2

Now, by <u>REMAINDER THEOREM</u>:

Dividend  = (Divisor x Quotient)  + Remainder

If ( x -3 ) divides the given polynomial with a remainder -2.

⇒  x = 3  is a  solution of given polynomial E(x)  - (-2) =  

E(x)  - (-2)  = 4x^2-p(x)+7 -(-2)  = 4x^2-p(x)+9 =  S(x)

Now, S(3) = 0

⇒4x^2-p(x)+9 = 4(3)^2 - p(3) + 9 = 0\\\implies 36 - 3p + 9 = 0\\\implies 45= 3p , \\or p  =15

or, p =1 5

Hence, for p = 15,  4x^2-p(x)+7 leaves a remainder of -2 when divided by (x-3).

6 0
3 years ago
EXTRA POINTS * how do you graph y=2x + 1
ahrayia [7]

Step-by-step explanation:

first u need to pick a random coordinate to substitute the X . example 0

y = 2(0) + 1

y =1 , X= 0

X= 1

y= 2(1) + 1

y= 3, X= 1

then you continue this same process and again until u have at least two points to draw a straight line. it kinda depended if u want to fill the entire graph.

3 0
4 years ago
An Internet reaction time test asks subjects to click their mouse button as soon as a light flashes on the screen. The light is
Ganezh [65]

Answer:

(a) 0.20

(b) 31%

(c) 2.52 seconds

Step-by-step explanation:

The random variable <em>Y</em> models the amount of time the subject has to wait for the light to flash.

The density curve represents that of an Uniform distribution with parameters <em>a</em> = 1 and <em>b</em> = 5.

So, Y\sim Unif(1,5)

(a)

The area under the density curve is always 1.

The length is 5 units.

Compute the height as follows:

\text{Area under the density curve}=\text{length}\times \text{height}

                                          1=5\times\text{height}\\\\\text{height}=\frac{1}{5}\\\\\text{height}=0.20

Thus, the height of the density curve is 0.20.

(b)

Compute the value of P (Y > 3.75) as follows:

P(Y>3.75)=\int\limits^{5}_{3.75} {\frac{1}{b-a}} \, dy \\\\=\int\limits^{5}_{3.75} {\frac{1}{5-1}} \, dy\\\\=\frac{1}{4}\times [y]^{5}_{3.75}\\\\=\frac{5-3.75}{4}\\\\=0.3125\\\\\approx 0.31

Thus, the light will flash more than 3.75 seconds after the subject clicks "Start" 31% of the times.

(c)

Compute the 38th percentile as follows:

P(Y

Thus, the 38th percentile is 2.52 seconds.

4 0
3 years ago
1.13 Thank you! (Sorry it’s so blurry)
VikaD [51]
\sqrt[8]{48^4}  can be rewritten as 48^4 to the \frac{1}{8}  power:

(48^4)^ \frac{1}{8}

Now, applying exponent rules (multiply exponent inside parentheses by the one outside parentheses), we get:

(48^ \frac{1}{2})

This is equivalent to \sqrt{48}, so now, we just simplify:

\sqrt{48}=  \sqrt{16*3}= \sqrt{16}* \sqrt{3}=4 \sqrt{3}

So:

\sqrt[8]{48^4} =4 \sqrt{3} 


4 0
4 years ago
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