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Eva8 [605]
4 years ago
7

When comparing alternative methods for making information systems identification and selection decisions, top management's selec

tion decisions often involve a small system size and have a cross-functional focus.
a.true
b.false
Computers and Technology
1 answer:
Softa [21]4 years ago
3 0

Answer: b) False

Explanation:

Alternative method that is used for information system consisting of prototyping, outsourcing, end-user development mechanism, system life cycle etc for building a system.

  • These process consist of focusing on user requirement, using high level programming languages, development of prototype,creation of package, database etc instead of cross-sectional phase,selection decisions,top management option etc.
  • Therefore, the correct option is option(b) as the statement is false.
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Primary storage is electronic storage connected directly to the CPU. true or false​
Helen [10]

Answer:

I think it's true

Explanation:

I don't know but If I'm wrong tell me?

7 0
2 years ago
To change the size of a field or record by dragging its border a.resize b.magnify c.label d.enlarge
4vir4ik [10]
A. Resize

By dragging the border of a field or record, you are either enlarging it or compressing it. Choices "b" and "d" are only half correct, as there is always the possibility of making it smaller. Hope this helps!
6 0
3 years ago
Read 2 more answers
Given an int variable n that has been initialized to a positive value and, in addition, int variables k and total that have alre
Fudgin [204]

Answer:

The c++ program to implement the while loop is given below.

#include <iostream>

using namespace std;

int main() {

  // declaration of integer variables

   int k, n, total;

   // initialization of integer variables

   k=1, n=4, total=0;

//  loop executed till value of k becomes equal to value of n

   while( k <= n ){

       // cube of every integer is added to the variable total

       total = total + ( k * k * k );

       // value of k is incremented to go to the next number

k = k + 1 ;

   }  

   return 0;

}  

Explanation:

The program begins with the declaration of integer variables.  

int k, n, total;

This is followed by initialization of these variables.

k=1, n=4, total=0;

The while loop runs over the variable k which is initialized to 1. The loop runs till value of k reaches the value of integer n.

First, cube of k is computed and added to the variable total.

After first execution of the loop, total is initialized to the cube of 1.

Next, value of variable k is incremented by 1 so that k is initialized to next integer.

After first execution of the loop, k is incremented from 1 to 2.

while( k <= n )

{

total = total + ( k * k * k );

k = k + 1 ;

   }

When the value of k reaches the value of integer n, the cube of n is calculated and added to the variable, total.

When k is incremented, it becomes more than n and hence, loop gets terminated.

As the return type of main is int, the program terminates with the statement shown below.

return 0;

No output is displayed as it is not mentioned in the question.

No user input is taken as it is mentioned that integer variables are already initialized.

4 0
3 years ago
Give five examples of top level domain​
coldgirl [10]

Answer:  .com — Commercial businesses.

.org — Organizations (generally charitable).

.net — Network organizations.

.gov — U.S. government agencies.

.mil — Military.

.edu — Educational facilities, like universities.

Explanation:

5 0
3 years ago
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There is a simple method for constructing a magic square for any odd value of n:
DaniilM [7]

Answer:

See Explaination

Explanation:

class MagicSquare():

def __init__(self,side):

self.side=side

self.two_dimension=[]

for row in range(1,side+1):

row_line=[]

for col in range(1,side+1):

row_line.append(0)

self.two_dimension.append(row_line)

def display(self):

row=0

col=int((self.side-1)/2)

for i in range(1,self.side**2+1):

self.two_dimension[row][col]=i

row-=1

col+=1

if row==-1:

row=self.side-1

if col==self.side:

col=0

if self.two_dimension[row][col]==0:

continue

else:

row+=1

if row==self.side:

row==0

for line in self.two_dimension:

for num in line:

print("{0:>3}".format(num),end=" ")

print()

def main():

for i in range(1,14,2):

square=MagicSquare(i)

square.display()

print("----------------------------------------------------")

if __name__ == '__main__':

main()

3 0
4 years ago
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