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kap26 [50]
3 years ago
8

What is the distance between the points of (3,-5) and (8,7)

Mathematics
1 answer:
Sphinxa [80]3 years ago
3 0
Distance=√(x2−x1)2+(y2−y1)2 Distance = x 2 - ⁢ x 1 2 + y 2 - ⁢ y 1 2. Substitute the actual values of the points into the distance formula. √((8)−(3))2+((−7)−(−5))2 8 - ⁢ 3 2 + - 7 - ⁢ - 5 2. Simplify.
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What is a simpler form of the expression? -3(-4y+3)+7y please explain, i don’t understand it.
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Answer:

19y - 9

Step-by-step explanation:

We can use the acronym PEMDAS. First, we need to calculate -3(-4y+3) by distributing. This is -3 * (-4y) + (-3) * 3 = 12y - 9 so the expression becomes 12y - 9 + 7y. Next, we need to combine like terms. 12y and +7y are like terms since they both have y so combining them gives us 12y + 7y = 19y. -9 stays by itself since there are no other constants so the final answer is 19y - 9.

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The perimeter of a rectangle is 16.6km, and its area is 13.42km2. Find its length and width. length : km width : km
Otrada [13]

Answer:

l=5.12 & w=2.62

Step by step explanation:

A=l×w

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p = 2(l + w) \\ 16.6 = 2(l +  \frac{13.42}{l} ) \\ 16.6 = 2( \frac{ {l}^{2}  + 13.42}{l}) \\ 16.6 = 2(l + 13.42) \\ 16.6 = 2l + 26.84 \\ 2l = 26.84 - 16.6 \\ 2l = 10.24 \\ l =  \frac{10.24}{2}  \\ l = 5.12km

Since you have found the value of the length you can find the value.of the width.

w =  \frac{13.42}{l}  \\ w =  \frac{13.42}{5.12}  \\ w = 2.62km

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Answer:

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