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LUCKY_DIMON [66]

2 years ago

8

A pair of pants was 40% off the original price. The sale resulted in a $36 discount. What was the original price before the sale

?

1 answer:

Mama L [17]2 years ago

8 0

Answer:

$90.00

Step-by-step explanation:

40% of What is 36?

40/4 = 10 (10%)

36/4 = 9 (9 is 10% of the answer we are looking for)

Multiply both answers (9 and 10) by each other.

You get 90

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Xiao’s teacher asked him to rewrite the sum 60+90 as a product of GCF of two numbers and A sum . xiao wrote 3(20+30.what mistake

maks197457 [2]

The first thing we must do for this case is find the factors of each of the numbers.

We have then:

60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

90: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

Therefore the GCF is given by:

$GFC = 30$

So, by rewriting the sum we have:

$60 + 90 = 30 (2 + 3)$

The error is not having written the GCF multiplying.

Answer:

Xiao did not write the sum as the product of GCF and the sum of two numbers.

The correct expression is:

$60 + 90 = 30 (2 + 3)$

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Which equation is y = –6x^2 + 3x + 2 rewritten in vertex form? y = negative 6 (x minus 1) squared + 8 y = negative 6 (x + one-fo

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Answer:

$y = -6(x - \frac{1}{2})^2 -\frac{7}{2}$

Step-by-step explanation:

Given:

$y = -6x^2 + 3x + 2$

Required

Rewrite in vertex form

The vertex form of an equation is in form of: $y = a(x - h)^2+ k$

Solving: $y = -6x^2 + 3x + 2$

Subtract 2 from both sides

$y - 2 = -6x^2 + 3x + 2 - 2$

$y - 2 = -6x^2 + 3x$

Factorize expression on the right hand side by dividing through by the coefficient of x²

$y - 2 = -6(x^2 + \frac{3x}{-6})$

$y - 2 = -6(x^2 - \frac{3x}{6})$

$y - 2 = -6(x^2 - \frac{x}{2})$

Get a perfect square of coefficient of x; then add to both sides

------------------------------------------------------------------------------------

<em>Rough work</em>

The coefficient of x is $\frac{-1}{2}$

It's square is $(\frac{-1}{2})^2 = \frac{1}{4}$

Adding inside the bracket of $-6(x^2 - \frac{x}{2})$ to give: $-6(x^2 - \frac{x}{2} + \frac{1}{4})$

To balance the equation, the same expression must be added to the other side of the equation;

Equivalent expression is: $-6(\frac{1}{4})$

------------------------------------------------------------------------------------

The expression becomes

$y - 2 -6(\frac{1}{4})= -6(x^2 - \frac{x}{2} + \frac{1}{4})$

$y - 2 -\frac{6}{4}= -6(x^2 - \frac{x}{2} + \frac{1}{4})$

$y - 2 -\frac{3}{2}= -6(x^2 - \frac{x}{2} + \frac{1}{4})$

Factorize the expression on the right hand side

$y - 2 -\frac{3}{2}= -6(x - \frac{1}{2})^2$

$y - (2 +\frac{3}{2})= -6(x - \frac{1}{2})^2$

$y - (\frac{4+3}{2})= -6(x - \frac{1}{2})^2$

$y - (\frac{7}{2})= -6(x - \frac{1}{2})^2$

$y +\frac{7}{2} = -6(x - \frac{1}{2})^2$

Make y the subject of formula

$y = -6(x - \frac{1}{2})^2 -\frac{7}{2}$

<em>Solved</em>

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