Answer: Choice B) {3, 5, sqrt(34)}
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Explanation:
We can only have a right triangle if and only if a^2+b^2 = c^2 is a true equation. The 'c' is the longest side, aka hypotenuse. The legs 'a' and 'b' can be in any order you want.
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For choice A,
a = 2
b = 3
c = sqrt(10)
So,
a^2+b^2 = 2^2+3^2 = 4+9 = 13
but
c^2 = (sqrt(10))^2 = 10
which is not equal to 13 from above. Cross choice A off the list.
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Checking choice B
a = 3
b = 5
c = sqrt(34)
Square each equation
a^2 = 3^2 = 9
b^2 = 5^2 = 25
c^2 = (sqrt(34))^2 = 34
We can see that
a^2+b^2 = 9+25 = 34
which is exactly equal to c^2 above. This confirms the answer.
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Let's check choice C
a = 5, b = 8, c = 12
a^2 = 25, b^2 = 64, c^2 = 144
So,
a^2+b^2 = c^2
25+64 = 144
89 = 144
which is a false equation allowing us to cross choice C off the list.
Answer:
1/5, 4/5, 5/5
Step-by-step explanation:
1/5 is 20%
4/5 is 80%
5/5 is 100%
Answer:
$43.48
Step-by-step explanation:
58.89x.30=17.68
58.89-17.68=41.21
41.21x.055=2.27
41.21+2.27= $43.48
I have the same question! have you figured it out ??
Answer:
x=-6 y=-1
Step-by-step explanation:
// Solve equation [2] for the variable y
[2] y = -x - 7
// Plug this in for variable y in equation [1]
[1] 3x - 2•(-x -7) = -16
[1] 5x = -30
// Solve equation [1] for the variable x
[1] 5x = - 30
[1] x = - 6
// By now we know this much :
x = -6
y = -x-7
// Use the x value to solve for y
y = -(-6)-7 = -1
Solution :
{x,y} = {-6,-1}
