Answer:
the answer would be 4 because you multiply
Okay, first thing is you want to have x and y all alone. So you need to solve the equations.
Equation 1:
5x+4y=12 (you want to subtract 5x on both sides to get y on one side and x on the other)
5x+4y=12
<u>-5x -5x
</u><u> 4y=12-5x</u> (Now if you want x and y alone you want to divide 4 on both sides)
4
y=3-1.25x Now that's you equation
Equation 2: (Basically the same steps for the 1st equation)
3x-3y=18 (Subtract 3x on both sides)
<u>-3x -3x </u><u>
</u><u>-3y=18-3x </u> (Now you divided by -3 on both sides)
-3
y=-6+x (you might notice why is there only 1 x, well because -3 divided by -3 is going to be a positive 1. You can either put a "x" or a 1x, doesn't really matter).
now since you have the two equations simplified you want to solve by doing multi-step.
3-1.25x=-6+x (Now you want to add 1.25x so you can get rid of the negative x)
<u> +1.25x +1.25x
</u> 3= -6+2.25 (Remember x alone is like 1, so it's like 1+1.25, next you want to add 6 on both sides. So you have a number and a variable all alone).
3=-6+2.25x
<u>+6 +6
</u><u>9 </u><u>= </u><u>2.25x</u> (Next you divided 2.25 on both sides)
2.25 2.25
Answer:
x =4
If your not sure, you can plug in or replace x with 4. :D
<em>I really do hope this help you understand :D </em>
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<h3>
<u>Answer:</u></h3>
<h3>
<u>Step-by-step explanation:</u></h3>
No , theres not enough information provided to Prove that both the triangles are congruent. Here in the figure we can see that there are two triangles ∆ BDA and ∆ BDC. And its given that
- AB = BC
- BD = BD ( common side )
The congruence conditions for two ∆s are :-
1) SAS ( Side Angle Side )
→ Two triangles are said to be congruent by SAS if two respective sides of the two triangles and the included angle between two sides are equal.
2) AAS ( Angle Angle Side )
→ Two triangles are said to be congruent by AAS if two angles and one side of triangle is congruent to other two angles and one side of the triangle .
3) SSS ( Side Side Side )
→ Two triangles are said to be congruent by SAS if all the three sides of one triangle is equal to three sides of the other triangle.
4) RHS ( Right Hypotenuse Side )
→ In two right-angled triangles, if the length of the hypotenuse and one side of one triangle, is equal to the length of the hypotenuse and corresponding side of the other triangle, then the two triangles are congruent.
And the given data doesn't satisfies any of the conditions.
<h3>
<u>Hence </u><u>there</u><u> </u><u>is</u><u> </u><u>not</u><u> </u><u>enough</u><u> </u><u>information</u><u> provided</u><u> </u><u>to</u><u> </u><u>Prove </u><u>that </u><u>two</u><u> </u><u>triang</u><u>les</u><u> </u><u>are </u><u>cong</u><u>ruent</u><u> </u><u>.</u></h3>