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almond37 [142]
3 years ago
8

Mai biked 7 and 1/4 miles today, and Noah biked 3 5/8 miles. How many times the length of Noah's bike ride was Mai's bike ride?

Mathematics
1 answer:
mamaluj [8]3 years ago
7 0

Answer:

The distance cover by Mai's bike is 2 time the distance cover by Noah's bike

Step-by-step explanation:

Given as :

The distance cover by Mai's bike = d_1 = 7 \dfrac{1}{4} miles

I.e d_1 = \dfrac{28+1}{4} miles

Or, d_1 = \dfrac{29}{4} miles

The distance cover by Noah's bike = d_2 = 3 \dfrac{5}{8} miles

I.e d_2 = \dfrac{24 + 5}{8} miles

Or,  d_2 = \dfrac{29}{8} miles

let the number of times that Noah's bike ride was Mai's bike ride = n

So, The distance cover by Mai's bike = n × The distance cover by Noah's bike

Or, d_ = n ×  d_

Or, \dfrac{29}{4} miles =  n × \dfrac{29}{8} miles

Or, n = \frac{\frac{29}{4}}{\frac{29}{8}}

∴ n = \dfrac{8}{4}

I.e n = 2

Hence The distance cover by Mai's bike is 2 time the distance cover by Noah's bike  . Answer

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Answer:

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Step-by-step explanation:

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3. sd = 10$

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