Answer:
Answer: 3 1/2 and -10 1/2 are the two numbers.
Step-by-step explanation:
Let x and y be the two unknown numbers.
x+y=-7 [Given]
x-y=14 [Given]
x-y=14 [Given]
x=y+14 [Add y to both sides]
x+y=-7 [Given]
(y+14)+y=-7 [Subtitution]
2y+14=-7 [Combine like terms]
2y=-21 [Subtract 14 from both sides]
y=-21/2 [Divide both sides by 2]
y=-10 1/2 [Division]
x-y=14 [Given]
x=y+14 [Add y to both sides]
x=-10 1/2 + 14 [Substitution]
x= 3 1/2 [Addition]
Check:
x+y=-7 [Given]
3 1/2 + -10 1/2?=-7 [Substition]
-7=-7 [Addition]
QED
x-y=14 [Given]
3 1/2 - -10 1/2?=14 [Substitution]
3 1/2 + 10 1/2?=14 [Change the sign of the subtrahend and add]
14=14 [Addition]
QED
Answer: 3 1/2 and -10 1/2 are the two numbers.
Answer:
The other coordinate is (-6,19)
Step-by-step explanation:
(4,-7)
(x,y)
[(4+x)/2 , (-7+y)/2] = (-1,6)
(4 + x)/2 = -1
4 + x = -2
× = -6
(-7 + y)/2 = 6
-7 + y = 12
y = 19
(Correct me if i am wrong)
The ordered pair is a solution of x - y = 2 and 3y - x = 8 is (x, y) = (7, 5)
<h3><u>Solution:</u></h3>
Given two equations are:
x - y = 2 and 3y - x = 8
<em><u>To find: orderes pair i.e (x, y)</u></em>
Let us consider:
x - y = 2 ------- eqn 1
3y - x = 8 --------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "x" and "y"</u></em>
On rearranging eqn 2, we get
-x + 3y = 8 ------ eqn 3
Add eqn 1 and eqn 3
x - y = 2
-x + 3y = 8
(+) ---------------
0 + 2y = 10
2y = 10
<h3>y = 5</h3>
Therefore from eqn 1,
x - y = 2
x - 5 = 2
x = 5 + 2 = 7
<h3>x = 7</h3>
Thus the ordered pair to the given equations are (x, y) = (7, 5)
The set of integers can be listed:
... {-3, -2, -1, 0, 1, 2, 3, 4, 5}
The set of real numbers must be indicated:
... {x ∈ ℝ | -4 < x ≤ 5 }
Answer:
Multiple Choice Answer: domain (-∞, ∞), range f(x) ≥ 3