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const2013 [10]
3 years ago
10

Find the number of 4 digit numbers that can be formed using the digits 1,2,3,4,5 if no digits is no repeated

Mathematics
1 answer:
loris [4]3 years ago
4 0

Answer:

5 different numbers, 2 even

Step-by-step explanation:

Since we have 5 digits and they are non repeating we can use the permutation formula:

P(n, k) = \frac{n!}{k!}, $where $ k \leq n ; k, n \in \mathbb{N}

It gives us the amount of ways to arrange k objects out of n objects without repetition, but order does matter.

In our case the amount of 4 digit numbers that can be formed using the digits from 1 to 5 is: P(5, 4) = \frac{5!}{4!} = 5.

And out of those 5, only 2 are even

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MAXImum [283]
<span>D/5 = 4
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move 118 to the other side of the equation.

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