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const2013 [10]
3 years ago
10

Find the number of 4 digit numbers that can be formed using the digits 1,2,3,4,5 if no digits is no repeated

Mathematics
1 answer:
loris [4]3 years ago
4 0

Answer:

5 different numbers, 2 even

Step-by-step explanation:

Since we have 5 digits and they are non repeating we can use the permutation formula:

P(n, k) = \frac{n!}{k!}, $where $ k \leq n ; k, n \in \mathbb{N}

It gives us the amount of ways to arrange k objects out of n objects without repetition, but order does matter.

In our case the amount of 4 digit numbers that can be formed using the digits from 1 to 5 is: P(5, 4) = \frac{5!}{4!} = 5.

And out of those 5, only 2 are even

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Answer:

In order to do so, we need to use basic algebra. The angles in a kite add up to 360 degrees. so we form the following equation.

x + y + y + 16 = 360

x + y + y = 344 <----(360 -16)

Each letter or variable represents an angle measure. the measures of the three angles left. The 16 degrees is on the bottom of the kite and the angle opposite is the top angle. the two side angles will be the same measure that's why they are both y.

x + 2y = 344

The two side angles will be 90 or greater because there is only 1 acute angle. 90 is the smallest number that can be chosen. so we do the following.

Step-by-step explanation:

x + 2(90) = 344

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THE MAXIMUM WHOLE NUMBER MEASURE OF THE ANGLE OPPOSITE OF THE 16 DEGREE ACUTE ANGLE IS 164 DEGREES*

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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