Find the number of 4 digit numbers that can be formed using the digits 1,2,3,4,5 if no digits is no repeated
1 answer:
Answer:
5 different numbers, 2 even
Step-by-step explanation:
Since we have 5 digits and they are non repeating we can use the permutation formula:
It gives us the amount of ways to arrange k objects out of n objects without repetition, but order does matter.
In our case the amount of 4 digit numbers that can be formed using the digits from 1 to 5 is:
And out of those 5, only 2 are even
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Answer:
= n - 2
Step-by-step explanation:
Note the difference between consecutive terms is constant, that is
0 - (- 1) = 0 + 1 = 1
1 - 0 = 1
2 - 1 = 1
3 - 2 = 1
This indicates the sequence is arithmetic with n th term
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 1 and d = 1, thus
= - 1 + n - 1 = n - 2