Just move the point Once to right, and up 5 times
a. The general equation for a circle centered at 
with radius 
is
The described circle has equation
We know the circle passes through the origin. This means that the equation above holds for 
and 
. The distance between any point on the circle and its center is the radius, so we can use this fact to determine :
So the circle's equation is
b. If the distance between point B and the center is less than 
, then B lies inside the circle. If the distance is greater than , it falls outside the circle. Otherwise, if the distance is exactly , then B lies on the circle.
The distance from B to the center is
, so 
, which means B falls outside the circle.
Answer:
0
Step-by-step explanation:
Using the trigonometric identity
cotx = 
Given
3cotθ = 2 , then
3
= 2 ( multiply both sides by sinθ )
3cosθ = 2sinθ ( subtract 3cosθ from both sides )
2sinθ - 3cosθ = 0
Thus
= 
= 0
The substitution that should be used to rewrite 6(x+5)^2 + 5(x+5) - 4 = 0 is u = x + 5
<h3>Quadratic equations</h3>
These are equations that has a leading degree of 2. Given the expression
6(x+5)^2 + 5(x+5) - 4 = 0
In order to simplify this equation, we will replace the reoccuring term by a variable.
From the equation we can see that (x+5) is occuring the most. Let u = x + 5 so that:
6u^2 - 5u - 4 = 0
Hence the substitution that should be used to rewrite 6(x+5)^2 + 5(x+5) - 4 = 0 is u = x + 5
Learn more on quadratic equation here: brainly.com/question/1214333
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