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Paraphin [41]
3 years ago
13

NEED ASAP!!! Assessment items Each month, Helder volunteers x hours at the hospital and 8 hours at the local food bank. To find

how many hours he will spend volunteering over 3 months, Helder calculates: x + 8 + x + 8 + x + 8 What is another way Helder can calculate how many hours he will volunteer in total over the 3 months?
Drag and drop the equivalent expression in the box
3x+8
3(x+8)
x+24
x+8
Mathematics
1 answer:
iragen [17]3 years ago
5 0

Answer:

3(x+8) is the answer

Step-by-step explanation:

You want the total number of hours worked over 3 months which gives you 3x and you would then need 8 hours for 3 months which give you 3x+24. So you would need 3(x+8).

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Solve the equation 2x2 + 13x + 15 = 0 by factoring. Show all steps.
natita [175]

Answer:

(2x + 3)(x + 5)

Step-by-step explanation:

2x² + 3x + 15 = 0

(2x + 3)(x + 5)

2x + 3 = 0

2x = -3

x = -3/2

x + 5 = 0

x = -5

4 0
3 years ago
THE SEVEN APPLEWOMEN
Sliva [168]

Answer:

  zero

Step-by-step explanation:

If the same sum is received for the sale of 20 apples at price p as is received for the sale of 140 apples at price p, then we must have ...

  20p = 140p

  120p = 0 . . . . . . subtract 20p

  p = 0 . . . . . . . . . divide by 120

The price was zero.

7 0
3 years ago
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These figures are congruent. What is the measurement? pic below
larisa [96]

Answer:

i dont know

Step-by-step explanation:

7 0
2 years ago
The ratio of chaperones to students on a field trip is2:7 there are 14 chaperones on the field trip in all how many chaperones a
Luden [163]

Answer:

14 chaperones, 49 students

Step-by-step explanation:

6 0
3 years ago
What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?
Harman [31]

Answer:

\boxed{ \bold{ \huge{  \boxed{ \sf{ \: 14.25 \: \% \: }}}}}

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

<u>Finding </u><u>the </u><u>Interest</u>

The sum of principal and interest is called an amount.

From the definition,

\boxed{ \sf{Amount =  \: Principal + Interest}}

plug the values

⇒\sf{14550 = 6000 + Interest}

Swap the sides of the equation

⇒\sf{6000 + Interest = 14550}

Move 6000 to right hand side and change its sign

⇒\sf{Interest = 14550 - 6000}

Subtract 6000 from 14550

⇒\sf{Interest = \: 8550 \: }

Interest = $ 8550

<u>Finding </u><u>the </u><u>rate </u>

{ \boxed{ \sf{Rate =  \frac{Interest \times 100}{Principal \times Time}}}}

plug the values

⇒\sf{ Rate = \frac{8550  \times 100}{6000 \times 10} }

Calculate

⇒\sf{Rate =  \frac{855000}{60000} }

⇒\sf{Rate = 14.25 \: \% \: }

Hope I helped!

Best regards!!

8 0
3 years ago
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