Answer:
Solution given:
In right angled triangle
ABC.
with respect to <C=40°
opposite side=AB
adjacent=BC=DE=30ft
now
relationship between opposite side and adjacent
is given by tan angle
tan 40°=oppo/adjacent
tan40°=AB/30
AB=tan40*30
AB=25.2
<u>Now</u><u> </u>
<u>height</u><u> </u><u>of</u><u> </u><u>flagpole</u><u> </u><u>=</u><u>AB</u><u>+</u><u>BE</u><u>=</u><u>2</u><u>5</u><u>.</u><u>2</u><u>+</u><u>5</u><u>=</u><u>3</u><u>0</u><u>.</u><u>2</u><u>f</u><u>t</u>
<u>option</u><u> </u><u>4</u><u>t</u><u>h</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u>
<h2>
Answer:</h2>
Option: A is the correct answer.
The ordered pair of point I' are:
A) (-0.8,2.4)
<h2>
Step-by-step explanation:</h2>
We know than if any point A with vertices as (a,b) are dilated by a scale factor of k then the vertices of the transformed point is:
A(a,b) → A'(ka,kb)
We are given vertices of point I as:
I(-2,6)
Hence, the vertices of the transformed point I' after dilating by a scale factor of 2/5 is:
I(-2,6) → I'(-2×(2/5),6×(2/5))
⇒ I(-2,6) → I'(-0.8,2.4)
Hence, option: A is the answer.
A) (-0.8,2.4)