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2 years ago

Write each fraction or mixed number as a decimal 5/25

Mathematics

1 answer:

Setler [38]2 years ago

3 0

$\frac{1}{5}$
0.2

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Select all the statements about rotations that are true.

sladkih [1.3K]

Answer: we dont have options

Step-by-step explanation:

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3 years ago

Can someone show me the answer + how they got there? (x+4)(x-1)

Naily [24]

Answer:

x^2+3x-4

Step-by-step explanation:

x * x - x + 4x - 4

x^2 - x + 4x - 4

x^2 + 3x - 4

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3 years ago

Read 2 more answers

What is the reciprocal of 7 1/3

Akimi4 [234]

First, you have to change 7 1/3 to an improper fraction which is 22/3.
Then you have to flip the fraction upside down to get the reciprocal.

So the answer is 3/22

6 0

3 years ago

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

2 years ago

What is-6 5/6 in decimal form? -6.516 -6.3125

olga2289 [7]

The answer is -6.833333333

8 0

3 years ago