Answer:
The value at the end of year 2 is $4400.
Step-by-step explanation:
The best approach here is to determine the expression for the line depreciation and then calculate the depreciation value at x = 2 years.
A line is given by
where m is the slope and b the bias (aka y-intercept). You can determine both directly from what is given. The slope is change in y divided by change in x. We know that over 5 years the car loses (500-7000)=-6500 in value. So, the slope is m=-6500/5 (note the negative sign). At time 0, the y-intercept is 7000, since that is the initial value (at year 0). So our line function is fully identified:
and gives you the value of the car in any given year. To answer the question, we now plug in 2 as value of x:
The answer is b because the slope is 2 and the y intercept is 9
Answer:
= -3 (x-y)
Step-by-step explanation:
-5x - 4y + 2x + 7y
Collect the like terms by calculating the sum or difference of their coefficients
(-5+2)x
-3x
(-4+7)y
3y
-3x + 3y
Factor out -3 from the expression
-3 (x-y)
Answer:
2.9
Step-by-step explanation:
It just is
Answer:
x < -4 or x > 8
On a number line, make two arrows:
1) going towards left from -4 with an open circle at -4
2) going towards right from 8 with an open circle at 8
Step-by-step explanation:
l -4 +2x l -3 > 9
l -4 +2x l > 12
l 2x - 4 l > 12
2x - 4 > 12
2x > 16
x > 8
-2x + 4 > 12
-2x > 8
x < -4
On a number line, make two arrows:
1) going towards left from -4 with an open circle at -4
2) going towards right from 8 with an open circle at 8
