The balanced equation for the above reaction is as follows;
2Al + 3Br₂ --> 2AlBr₃
stoichiometry of Al to Br₂ is 2:3
there are 5.0 mol of Al and 6.0 mol of Br₂
if Al is the limiting reactant,
if 2 mol of Al reacts with 3 mol of Br₂
then 5.0 mol of Al reacts with - 3/2 x 5 = 7.5 mol of Br₂
but only 6 mol of Br₂ is present therefore Br₂ is the limiting reactant.
if 3 mol of Br₂ reacts with 2 mol of Al
then 6.0 mol of Br₂ reacts with - 2/3 x 6 = 4 mol of Al
the molar ratio of Al to AlBr₃ is 2:2
the number of moles of AlBr₃ formed is 4 mol of AlBr₃
amount of excess Al - 5.0 mol - 4.0 mol = 1 mol
therefore at the end of the reaction,
1 mol of Al and 4 mol of AlBr₃ in the reaction vessel
A. Breaking Bread, because you can rip or cut it and it is still bread.
hope that helps :)
Answer:
5.2 x 102m/s
Explanation:
v(rms) = square root of 3RT divided molar mass in kg
R =8.3J/molK T = 543 kelvin
3(8.3)(543)/.044=307289 m^2/s^2
square root 5.2X10^2 m/2
Answer:polar and non-polar molecules, positive parts of polar molecules and positive parts of non polar molecules
Explanation:
Answer:
It can be produced, 12 moles of MgO.
Option B
Explanation:
2 KClO₃ → 3O₂ + 2 KCl
Ratio in this reaction is 2:3
In the begining, I make 3 moles of oxygen, that came from 2moles of chlorate. If I have 4 moles of salt, let's make a rule of three.
2 moles of salt ___ make __3 moles of O₂
4 moles of salt ___ make (4 .3) /2 = 6 moles of O₂
2 Mg + O2 → 2 MgO.
From 1 mol of oxygen, I can make 2 moles of oxygen.
If I have 6 moles, I would make the double, though.