Answer:
The explanation to your question is below.
Explanation:
In thermochemistry, reactions are classify in two groups.
- Endothermic reactions: are reactions that need energy (heat) from the surroundings to happen. If they are not heated, the products will not form.
Example:
2 H₂O + energy ⇒ 2H₂ + O₂
-Exothermic reactions: are reactions that release energy to the surroundings. They happen spontaneously.
Example:
CH₄ + 2O₂ ⇒ CO₂ + 2H₂O + energy (heat)
The answer for the following problem is described below.
<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>
Explanation:
Given:
enthalpy of combustion of glucose(Δ
of 
) =-1275.0
enthalpy of combustion of oxygen(Δ of 
) = zero
enthalpy of combustion of carbon dioxide(Δ of 
) = -393.5
enthalpy of combustion of water(Δ of 
) = -285.8
To solve :
standard enthalpy of combustion
We know;
Δ = ∈Δ (products) - ∈Δ (reactants)
(s) +6 (g) → 6 (g)+ 6 (l)
Δ = [6 (-393.5) + 6(-285.8)] - [6 (0) + (-1275)]
Δ = [6 (-393.5) + 6(-285.8)] - [0 - 1275]
Δ = 6 (-393.5) + 6(-285.8) - 0 + 1275
Δ = -2361 - 1714 - 0 + 1275
Δ =-2800 kJ
<em><u> Therefore the standard enthalpy of combustion is -2800 kJ</u></em>
Answer: sodium metal and chlorine gas
Explanation:
Answer:
0.16 M
Explanation:
Molarity = moles/litres
= 0.06 moles/0.375 litres
= 0.16 M
Answer:
i would say 10, so the anser is A.
Explanation:
because there are the same number of protons and electrons, therefore for a regular O, you are supposed to have only 8 protons, but it is charged, thus, whatever the charge is will be taken into consideration into how much the proton and electron doe it have. Thus, for this case, it has 10, because the charge is negative and you have 8 electron plus 2 = 10.
