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I am Lyosha [343]
2 years ago
6

15. What will be the volume of a given mass of oxygen at 250C if it occupies 100cm3 at 150C.? (Pressure remain constant)​

Chemistry
1 answer:
butalik [34]2 years ago
3 0

Answer:

V₂ = 167 cm₃

Explanation:

Because you are only dealing with volume and temperature, you can use Charles' Law to find the missing value. This formula looks like this:

V₁ / T₁ = V₂ / T₂

In this formula, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You have been given values for all of the variables except for final volume. Therefore, by plugging these values into the formula, you can simplify to find your answer.

V₁ = 100 cm³             T₁ = 150 °C

V₂ = ?                        T₂ = 250 °C

V₁ / T₁ = V₂ / T₂                                          <---- Charles' Law formula

(100 cm³) / (150 °C) = V₂ / (250 °C)           <---- Insert values

(0.667) = V₂ / (250 °C)                               <---- Simplify left side

(0.667) x (250 °C) = V₂                              <---- Rearrange

167 = V₂                                                     <---- Simplify left side

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How much force is needed to accelerate a 56 kg skier at 3 m/s?
Aloiza [94]

Answer:

<h2>168 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 56 × 3

We have the final answer as

<h3>168 N</h3>

Hope this helps you

3 0
2 years ago
Calculate the pH of a buffer solution prepared by mixing 60.0 mL of 1.00 M lactic acid and 25.0 mL of 1.00 M sodium lactate.
marshall27 [118]
This problem could be solved easily using the Henderson-Hasselbach equation used for preparing buffer solutions. The equation is written below:

pH = pKa + log[(salt/acid]

Where salt represents the molarity of salt (sodium lactate), while acid is the molarity of acid (lactic acid). 

Moles of salt = 1 mol/L * 25 mL * 1 L/1000 mL = 0.025 moles salt
Moles of acid = 1 mol/L* 60 mL * 1 L/1000 mL = 0.06 moles acid
Total Volume = (25 mL + 60 mL)*(1 L/1000 mL) = 0.085 L

Molarity of salt = 0.025 mol/0.085 L = 0.29412 M
Molarity of acid = 0.06 mol/0.085 L = 0.70588 M

Thus,
pH = 3.86 + log(0.29412/0.70588)
pH = 3.48
4 0
3 years ago
According to the Law of Conservation of Mass, how much water is produced if 22.5 g of
nadezda [96]

Answer: The amount of water produced is 9.3 grams

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

CH_4+2O_2\rightarrow CO_2+2H_2O

mass of reactants = mass of methane + mass of oxygen = 22.5 g + 35.7 g = 58.2 g

mass of products = mass of carbon dioxide + mass of water = 48.9 g +  mass of water

48.9 g +  mass of water = 58.2 g

mass of water = 9.3 g

4 0
3 years ago
Find the % composition for each element in Zn(CIO3)2
bezimeni [28]

Zn = 28.15%

Cl = 30.53%

O = 41.32%

<h3>Further explanation</h3>

Given

Zn(CIO3)2 compound

Required

The % composition

Solution

Ar Zn = 65.38

Ar Cl = 35,453

Ar O = 15,999

MW Zn(CIO3)2 = 232.3

Zn = 65,38/232.3 x 100% = 28.15%

Cl = (2 x 35.453) / 232.3 x 100% = 30.53%

O = (6 x 15.999) / 232.3 x 100% = 41.32%

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lapo4ka [179]
1. Liquid
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