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strojnjashka [21]
3 years ago
5

Expand the following a. 2(x+3) b. 5(2x-4) c. 4(2x+1) d. 6(x-4y)!

Mathematics
2 answers:
vovikov84 [41]3 years ago
4 0
So you multiply the number in front (left) of the bracket with the values inside the brackets so
a. it’s 2 multiply x plus 2 multiply 3 which gets you 2x + 6
b. 5 multiply 2x and 5 multiply -4 = 10x - 20
c. 4 multiply 2x and 4 multiply 1 = 8x + 4
d. 6 multiply x and 6 multiply -4y = 6x - 24y
arsen [322]3 years ago
3 0

Answer:

Step-by-step explanation:

2x+6

10x-20

8x+4

6x-24y

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If x varies as y and if x=20 when y=9 , find x when y=18​
andrezito [222]

Answer:1/2 y

Step-by-step explanation:

We can solve this using ration reasoning:  

x

2

x

1

=

y

2

y

1

Explanation:

If  

x

varies directly with  

y

(written  

x

∝

y

), then doubling  

y

means doubling  

x

, so the rations of final values and initial values will be the same:

x

2

x

1

=

y

2

y

1

In this case,

x

2

9

=

24

18

x

2

=

9

⋅

24

18

=

12

Or, intuitively, if  

x

∝

y

and  

x

=

9

when  

y

=

18

, we can conclude that

x

=

1

2

y

and  

1

2

of 24 is 12.

3 0
3 years ago
Solve the equation on the interval [0, 2pi): 12cos^2 x-9=0<br><br><br> What to do?
siniylev [52]

Answer:

\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}}

Step-by-step explanation:

12\cos^2x-9=0\qquad\text{add 9 to both sides}\\\\12\cos^2x=9\qquad\text{divide both sides by 12}\\\\\cos^2x=\dfrac{9}{12}\\\\\cos^2x=\dfrac{9:3}{12:3}\\\\\cos^2x=\dfrac{3}{4}\to\cos x=\pm\sqrt{\dfrac{3}{4}}\\\\\cos x=\pm\dfrac{\sqrt3}{2}\\\\\text{Look at the picture}\\\\x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}

6 0
3 years ago
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