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Luden [163]
3 years ago
14

Solve the following system of equations using Gaussian elimination method. If there are no solutions, type "N" for both xx, yy a

nd zz. If there are infinitely many solutions, type "z" for zz, and expressions in terms of zz for xx and yy.-5x-7y-4z=-66x+2y+3z=-2-1x+2y-7z=0
Mathematics
1 answer:
Anna11 [10]3 years ago
6 0

Answer:

x=-224/229,

y=296/229,

z=118/229

Step-by-step explanation:

-5x-7y-4z=-6

6x+2y+3z=-2

-x+2y-7z=0...........( multiple with (-5) and sum with 1st equation, mult with 6 and                    sum with 2nd equation)

______________

-x+2y-7z=0

-17y+31z=-6.....(mult with 14)

14y-39z=-2.....(mult with -17) then sum

___________

-x+2y-7z=0

-229z=-118, so here we have z=118/229.

14y-39*(118/229)=-2, from here we have y=296/229

-x+2*(296/229)-7*(118/229)=0, we get that x=-234/229

In the same way you can do this in the matrix form>>

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